Explanation Given Information: The rate at which the height of the particle is changing is, v = 320 − 32 t in feet per second And the particle is at 1600 feet when t = 10 seconds. Formula used: The power rule of integrals, ∫ x n d x = x n + 1 n + 1 + C ( n ≠ 1 ) Calculation: As it is provided that the rate at which the height of the particle is changing is, v = 320 − 32 t in feet per second Now, the rate of change of height can be obtained by differentiating the height equation as, h ′ ( t ) = 320 − 32 t Thus, the height function can be obtained by integrating the above function as, h ( t ) = ∫ 320 − 32 t d t Now, integrate the above function using power rule of integrals as, h ( t )

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ISBN: 9781305713864

Author: HARSHBARGER

Publisher: CENGAGE L

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Chapter 12.1, Problem 46E

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To calculate: The equation that describes the height of the particle at time t if the rate at which its height is changing is v=320−32t in feet per second and it is at 1600 feet when t=10 seconds.

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Chapter 12.1, Problem 45E

Chapter 12.1, Problem 47E

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The equation that describes the height of the particle at time t if the rate at which its height is changing is v = 320 − 32 t in feet per second and it is at 1600 feet when t = 10 seconds.

Solution Summary: The author calculates the height of the particle at time t if its height is changing at a rate of 320-32t in feet per second.

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To calculate: The equation that describes the height of the particle at time t if the rate at which its height is changing is v=320−32t in feet per second and it is at 1600 feet when t=10 seconds.

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Chapter 12 Solutions