Explanation Given Information: The provided population of bacteria grows at the rate, d p d t = 100 , 000 ( t + 100 ) 2 . Where p is the population and t is time. The population of the bacteria is 1000 when t = 1 . Formula used: According to the power rule of integrals, d d x ( x n ) = x n + 1 n + 1 + C Calculation: Consider the rate at which the population of bacteria grows, d p d t = 100 , 000 ( t + 100 ) 2 Where p is the population and t is time. Now, the rate of population growth can be obtained by differentiating the population function as, P ′ ( t ) = 100 , 000 ( t + 100 ) 2 Thus, the population function can be obtained by integrating the above function as, P ( t ) = ∫ 100 , 000 ( t + 100 ) 2 d x

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Author: HARSHBARGER

Publisher: CENGAGE L

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Chapter 12, Problem 38RE

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To calculate: The equation which provides the size of population at the time t. If a population of bacteria grows at the rate dpdt=100,000(t+100)2.

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Chapter 12, Problem 37RE

Chapter 12, Problem 39RE

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Chapter 12 Solutions

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The equation which provides the size of population at the time t . If a population of bacteria grows at the rate d p d t = 100 , 000 ( t + 100 ) 2 .

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To calculate: The equation which provides the size of population at the time t. If a population of bacteria grows at the rate dpdt=100,000(t+100)2.

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