The degrees of freedom for group, for error, and for the total.

Question

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Answer 1

Question

Chapter 12.1, Problem 19E

(a)

Section 1:

To determine

To find: The degrees of freedom for group, for error, and for the total.

(a)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE =72, and DFT=74_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=3×25=75

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=75−3=72

DFT=N−1=75−1=74

Section 2:

To determine

To find: The degrees of freedom for group, for error, and for the total.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE=91, and DFT=93_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=94

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=94−3=91

DFT=N−1=94−1=93

Section 3:

To determine

To find: The degrees of freedom for group, for error, and for the total.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE=39, and DFT=41_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=42

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=42−3=39

DFT=N−1=42−1=41

(b)

Section 1:

To determine

To explain: The Null and alternative hypotheses for cholesterol level in egg.

(b)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the treatment means are equal.

Alternative Hypothesis: At least two of the treatment means differ significantly.

Explanation of Solution

The null hypothesis is that there is no difference in the effect of three treatments on egg against the alternative hypothesis that not all the effects are equal that is, at least one effect will differ significantly from the other at the provided confidence level.

Section 2:

To determine

To explain: The Null and alternative hypotheses for rating on a seven point scale.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the three types of students gave same mean ratings.

Alternative Hypothesis: The average ratings of at least two sources of response differ significantly.

Explanation of Solution

The null hypothesis assumes that there is no significant difference in ratings against the alternative hypothesis that not all the ratings are equal that is, at least one rating will differ significantly from other at the desired level of significance.

Section 3:

To determine

The Null and alternative hypotheses for quiz score.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the three groups of students have same mean scores.

Alternative Hypothesis: The mean score of at least two groups differ significantly.

Explanation of Solution

The null hypothesis assumes that there is no difference in quiz score of the three groups against the alternative hypothesis that not all the scores are equal that is, at least one score will differ significantly from other at the provided confidence level.

(c)

Section 1:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

(c)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,72)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=72

Thus, the F statistic is represented as,

F(I−1,N−I)=F(2,72)

Section 2:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,91)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=91

Hence F statistic is represented as

F(I−1,N−I)=F(2,91)

Section 3:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,39)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=39

Hence, F statistic is represented as,

F(I−1,N−I)=F(2,39)

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Answer 2

Question

Chapter 12.1, Problem 19E

(a)

Section 1:

To determine

To find: The degrees of freedom for group, for error, and for the total.

(a)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE =72, and DFT=74_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=3×25=75

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=75−3=72

DFT=N−1=75−1=74

Section 2:

To determine

To find: The degrees of freedom for group, for error, and for the total.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE=91, and DFT=93_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=94

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=94−3=91

DFT=N−1=94−1=93

Section 3:

To determine

To find: The degrees of freedom for group, for error, and for the total.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE=39, and DFT=41_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=42

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=42−3=39

DFT=N−1=42−1=41

(b)

Section 1:

To determine

To explain: The Null and alternative hypotheses for cholesterol level in egg.

(b)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the treatment means are equal.

Alternative Hypothesis: At least two of the treatment means differ significantly.

Explanation of Solution

The null hypothesis is that there is no difference in the effect of three treatments on egg against the alternative hypothesis that not all the effects are equal that is, at least one effect will differ significantly from the other at the provided confidence level.

Section 2:

To determine

To explain: The Null and alternative hypotheses for rating on a seven point scale.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the three types of students gave same mean ratings.

Alternative Hypothesis: The average ratings of at least two sources of response differ significantly.

Explanation of Solution

The null hypothesis assumes that there is no significant difference in ratings against the alternative hypothesis that not all the ratings are equal that is, at least one rating will differ significantly from other at the desired level of significance.

Section 3:

To determine

The Null and alternative hypotheses for quiz score.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the three groups of students have same mean scores.

Alternative Hypothesis: The mean score of at least two groups differ significantly.

Explanation of Solution

The null hypothesis assumes that there is no difference in quiz score of the three groups against the alternative hypothesis that not all the scores are equal that is, at least one score will differ significantly from other at the provided confidence level.

(c)

Section 1:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

(c)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,72)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=72

Thus, the F statistic is represented as,

F(I−1,N−I)=F(2,72)

Section 2:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,91)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=91

Hence F statistic is represented as

F(I−1,N−I)=F(2,91)

Section 3:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,39)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=39

Hence, F statistic is represented as,

F(I−1,N−I)=F(2,39)

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Answer 3

Question

Chapter 12.1, Problem 19E

(a)

Section 1:

To determine

To find: The degrees of freedom for group, for error, and for the total.

(a)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE =72, and DFT=74_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=3×25=75

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=75−3=72

DFT=N−1=75−1=74

Section 2:

To determine

To find: The degrees of freedom for group, for error, and for the total.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE=91, and DFT=93_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=94

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=94−3=91

DFT=N−1=94−1=93

Section 3:

To determine

To find: The degrees of freedom for group, for error, and for the total.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE=39, and DFT=41_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=42

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=42−3=39

DFT=N−1=42−1=41

(b)

Section 1:

To determine

To explain: The Null and alternative hypotheses for cholesterol level in egg.

(b)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the treatment means are equal.

Alternative Hypothesis: At least two of the treatment means differ significantly.

Explanation of Solution

The null hypothesis is that there is no difference in the effect of three treatments on egg against the alternative hypothesis that not all the effects are equal that is, at least one effect will differ significantly from the other at the provided confidence level.

Section 2:

To determine

To explain: The Null and alternative hypotheses for rating on a seven point scale.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the three types of students gave same mean ratings.

Alternative Hypothesis: The average ratings of at least two sources of response differ significantly.

Explanation of Solution

The null hypothesis assumes that there is no significant difference in ratings against the alternative hypothesis that not all the ratings are equal that is, at least one rating will differ significantly from other at the desired level of significance.

Section 3:

To determine

The Null and alternative hypotheses for quiz score.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the three groups of students have same mean scores.

Alternative Hypothesis: The mean score of at least two groups differ significantly.

Explanation of Solution

The null hypothesis assumes that there is no difference in quiz score of the three groups against the alternative hypothesis that not all the scores are equal that is, at least one score will differ significantly from other at the provided confidence level.

(c)

Section 1:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

(c)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,72)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=72

Thus, the F statistic is represented as,

F(I−1,N−I)=F(2,72)

Section 2:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,91)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=91

Hence F statistic is represented as

F(I−1,N−I)=F(2,91)

Section 3:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,39)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=39

Hence, F statistic is represented as,

F(I−1,N−I)=F(2,39)

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Answer 4

Question

Chapter 12.1, Problem 19E

(a)

Section 1:

To determine

To find: The degrees of freedom for group, for error, and for the total.

(a)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE =72, and DFT=74_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=3×25=75

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=75−3=72

DFT=N−1=75−1=74

Section 2:

To determine

To find: The degrees of freedom for group, for error, and for the total.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE=91, and DFT=93_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=94

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=94−3=91

DFT=N−1=94−1=93

Section 3:

To determine

To find: The degrees of freedom for group, for error, and for the total.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE=39, and DFT=41_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=42

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=42−3=39

DFT=N−1=42−1=41

(b)

Section 1:

To determine

To explain: The Null and alternative hypotheses for cholesterol level in egg.

(b)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the treatment means are equal.

Alternative Hypothesis: At least two of the treatment means differ significantly.

Explanation of Solution

The null hypothesis is that there is no difference in the effect of three treatments on egg against the alternative hypothesis that not all the effects are equal that is, at least one effect will differ significantly from the other at the provided confidence level.

Section 2:

To determine

To explain: The Null and alternative hypotheses for rating on a seven point scale.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the three types of students gave same mean ratings.

Alternative Hypothesis: The average ratings of at least two sources of response differ significantly.

Explanation of Solution

The null hypothesis assumes that there is no significant difference in ratings against the alternative hypothesis that not all the ratings are equal that is, at least one rating will differ significantly from other at the desired level of significance.

Section 3:

To determine

The Null and alternative hypotheses for quiz score.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the three groups of students have same mean scores.

Alternative Hypothesis: The mean score of at least two groups differ significantly.

Explanation of Solution

The null hypothesis assumes that there is no difference in quiz score of the three groups against the alternative hypothesis that not all the scores are equal that is, at least one score will differ significantly from other at the provided confidence level.

(c)

Section 1:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

(c)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,72)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=72

Thus, the F statistic is represented as,

F(I−1,N−I)=F(2,72)

Section 2:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,91)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=91

Hence F statistic is represented as

F(I−1,N−I)=F(2,91)

Section 3:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,39)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=39

Hence, F statistic is represented as,

F(I−1,N−I)=F(2,39)

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Answer 5

Chapter 12.1, Problem 19E

(a)

Section 1:

To determine

To find: The degrees of freedom for group, for error, and for the total.

(a)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE =72, and DFT=74_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=3×25=75

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=75−3=72

DFT=N−1=75−1=74

Section 2:

To determine

To find: The degrees of freedom for group, for error, and for the total.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE=91, and DFT=93_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=94

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=94−3=91

DFT=N−1=94−1=93

Section 3:

To determine

To find: The degrees of freedom for group, for error, and for the total.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE=39, and DFT=41_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=42

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=42−3=39

DFT=N−1=42−1=41

(b)

Section 1:

To determine

To explain: The Null and alternative hypotheses for cholesterol level in egg.

(b)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the treatment means are equal.

Alternative Hypothesis: At least two of the treatment means differ significantly.

Explanation of Solution

The null hypothesis is that there is no difference in the effect of three treatments on egg against the alternative hypothesis that not all the effects are equal that is, at least one effect will differ significantly from the other at the provided confidence level.

Section 2:

To determine

To explain: The Null and alternative hypotheses for rating on a seven point scale.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the three types of students gave same mean ratings.

Alternative Hypothesis: The average ratings of at least two sources of response differ significantly.

Explanation of Solution

The null hypothesis assumes that there is no significant difference in ratings against the alternative hypothesis that not all the ratings are equal that is, at least one rating will differ significantly from other at the desired level of significance.

Section 3:

To determine

The Null and alternative hypotheses for quiz score.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the three groups of students have same mean scores.

Alternative Hypothesis: The mean score of at least two groups differ significantly.

Explanation of Solution

The null hypothesis assumes that there is no difference in quiz score of the three groups against the alternative hypothesis that not all the scores are equal that is, at least one score will differ significantly from other at the provided confidence level.

(c)

Section 1:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

(c)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,72)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=72

Thus, the F statistic is represented as,

F(I−1,N−I)=F(2,72)

Section 2:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,91)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=91

Hence F statistic is represented as

F(I−1,N−I)=F(2,91)

Section 3:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,39)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=39

Hence, F statistic is represented as,

F(I−1,N−I)=F(2,39)

Answer 6

Chapter 12.1, Problem 19E

(a)

Section 1:

To determine

To find: The degrees of freedom for group, for error, and for the total.

(a)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE =72, and DFT=74_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=3×25=75

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=75−3=72

DFT=N−1=75−1=74

Answer 7

Chapter 12.1, Problem 19E

(a)

Section 1:

To determine

To find: The degrees of freedom for group, for error, and for the total.

Answer 8

(a)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE =72, and DFT=74_.

Answer 9

(a)

Section 1:

Expert Solution

Answer 10

(a)

Section 1:

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=3×25=75

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=75−3=72

DFT=N−1=75−1=74

Answer 13

Section 2:

To determine

To find: The degrees of freedom for group, for error, and for the total.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE=91, and DFT=93_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=94

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=94−3=91

DFT=N−1=94−1=93

Answer 14

Section 2:

To determine

To find: The degrees of freedom for group, for error, and for the total.

Answer 15

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE=91, and DFT=93_.

Answer 16

Section 2:

Expert Solution

Answer 17

Section 2:

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=94

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=94−3=91

DFT=N−1=94−1=93

Answer 20

Section 3:

To determine

To find: The degrees of freedom for group, for error, and for the total.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE=39, and DFT=41_.

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=42

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=42−3=39

DFT=N−1=42−1=41

Answer 21

Section 3:

To determine

To find: The degrees of freedom for group, for error, and for the total.

Answer 22

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are DFG=2, DFE=39, and DFT=41_.

Answer 23

Section 3:

Expert Solution

Answer 24

Section 3:

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Calculation: The variable I represents the number of groups and the variable N represents the total number of observations. According to the information given in the question

I=3N=42

If DFG, DFE and DFT represent the group, error and total degrees of freedom respectively then they are calculated as shown below,

DFG=I−1=3−1=2

DFE=N−I=42−3=39

DFT=N−1=42−1=41

Answer 27

(b)

Section 1:

To determine

To explain: The Null and alternative hypotheses for cholesterol level in egg.

(b)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the treatment means are equal.

Alternative Hypothesis: At least two of the treatment means differ significantly.

Explanation of Solution

The null hypothesis is that there is no difference in the effect of three treatments on egg against the alternative hypothesis that not all the effects are equal that is, at least one effect will differ significantly from the other at the provided confidence level.

Answer 28

(b)

Section 1:

To determine

To explain: The Null and alternative hypotheses for cholesterol level in egg.

Answer 29

(b)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the treatment means are equal.

Alternative Hypothesis: At least two of the treatment means differ significantly.

Answer 30

(b)

Section 1:

Expert Solution

Answer 31

(b)

Section 1:

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

The null hypothesis is that there is no difference in the effect of three treatments on egg against the alternative hypothesis that not all the effects are equal that is, at least one effect will differ significantly from the other at the provided confidence level.

Answer 34

Section 2:

To determine

To explain: The Null and alternative hypotheses for rating on a seven point scale.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the three types of students gave same mean ratings.

Alternative Hypothesis: The average ratings of at least two sources of response differ significantly.

Explanation of Solution

The null hypothesis assumes that there is no significant difference in ratings against the alternative hypothesis that not all the ratings are equal that is, at least one rating will differ significantly from other at the desired level of significance.

Answer 35

Section 2:

To determine

To explain: The Null and alternative hypotheses for rating on a seven point scale.

Answer 36

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the three types of students gave same mean ratings.

Alternative Hypothesis: The average ratings of at least two sources of response differ significantly.

Answer 37

Section 2:

Expert Solution

Answer 38

Section 2:

Expert Solution

Answer 39

Expert Solution

Answer 40

Explanation of Solution

The null hypothesis assumes that there is no significant difference in ratings against the alternative hypothesis that not all the ratings are equal that is, at least one rating will differ significantly from other at the desired level of significance.

Answer 41

Section 3:

To determine

The Null and alternative hypotheses for quiz score.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the three groups of students have same mean scores.

Alternative Hypothesis: The mean score of at least two groups differ significantly.

Explanation of Solution

The null hypothesis assumes that there is no difference in quiz score of the three groups against the alternative hypothesis that not all the scores are equal that is, at least one score will differ significantly from other at the provided confidence level.

Answer 42

Section 3:

To determine

The Null and alternative hypotheses for quiz score.

Answer 43

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required hypotheses are,

Null Hypothesis: All the three groups of students have same mean scores.

Alternative Hypothesis: The mean score of at least two groups differ significantly.

Answer 44

Section 3:

Expert Solution

Answer 45

Section 3:

Expert Solution

Answer 46

Expert Solution

Answer 47

Explanation of Solution

The null hypothesis assumes that there is no difference in quiz score of the three groups against the alternative hypothesis that not all the scores are equal that is, at least one score will differ significantly from other at the provided confidence level.

Answer 48

(c)

Section 1:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

(c)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,72)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=72

Thus, the F statistic is represented as,

F(I−1,N−I)=F(2,72)

Answer 49

(c)

Section 1:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

Answer 50

(c)

Section 1:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,72)_.

Answer 51

(c)

Section 1:

Expert Solution

Answer 52

(c)

Section 1:

Expert Solution

Answer 53

Expert Solution

Answer 54

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=72

Thus, the F statistic is represented as,

F(I−1,N−I)=F(2,72)

Answer 55

Section 2:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,91)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=91

Hence F statistic is represented as

F(I−1,N−I)=F(2,91)

Answer 56

Section 2:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

Answer 57

Section 2:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,91)_.

Answer 58

Section 2:

Expert Solution

Answer 59

Section 2:

Expert Solution

Answer 60

Expert Solution

Answer 61

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=91

Hence F statistic is represented as

F(I−1,N−I)=F(2,91)

Answer 62

Section 3:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,39)_.

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=39

Hence, F statistic is represented as,

F(I−1,N−I)=F(2,39)

Answer 63

Section 3:

To determine

To find: The degrees of freedom for numerator and denominator of F statistic.

Answer 64

Section 3:

Expert Solution

Answer to Problem 19E

Solution: The required degrees of freedom are (2,39)_.

Answer 65

Section 3:

Expert Solution

Answer 66

Section 3:

Expert Solution

Answer 67

Expert Solution

Answer 68

Explanation of Solution

Calculation: In F statistic, the degrees of freedom for numerator are given by DFG=I−1 and denominator degrees of freedom are given by DFE=N−I. From part (a) the degrees of freedom are,

DFG=2 and DFE=39

Hence, F statistic is represented as,

F(I−1,N−I)=F(2,39)