CHEMISTRY THE CENTRAL SCIENCE >EBOOK<
CHEMISTRY THE CENTRAL SCIENCE >EBOOK<
14th Edition
ISBN: 9780136873891
Author: Brown
Publisher: PEARSON
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Chapter 12, Problem 8E

(a)

Interpretation Introduction

Interpretation: The band that is the valence band should be determined.

Concept Introduction:The band that forms from bonding molecular orbital in a semiconductor is called the valence band

(b)

Interpretation Introduction

Interpretation: The band that is the conduction band should be determined.

Concept Introduction: The band that forms from anti-bonding molecular orbital in a semiconductor is called the conduction band.

(c)

Interpretation Introduction

Interpretation: The region of the diagram that represents the band gap should be determined.

Concept Introduction: The band gap is the gap between the valence band and conduction band.

(d)

Interpretation Introduction

Interpretation: The band that consists of bonding molecular orbital should be determined.

Concept Introduction:The band that forms from bonding molecular orbital in a semiconductor is called the valence band that contains bonding molecular orbital

(e)

Interpretation Introduction

Interpretation: The type of semiconductor represented by the diagram should be explained.

Concept Introduction:An n-type semiconductor is one in which the dopant element has more number of valence electrons than the host element and this leads to an increase in number of negatively charged electrons in the conduction band that can move easily. So, in an n-type semiconductor conduction band is not completely empty.

A p-type semiconductor is one in which the dopant element has less number of valence electrons than the host element and this leads to electron vacancies, known as holes, in the valence band. Thus in a p-type semiconductor the valence band has electron vacancies and is not completely filled with electrons.

(f)

Interpretation Introduction

Interpretation: The elements that could be dopant from the given elements Ga , Si or P , if the semiconductor is germanium should be determined.

Concept Introduction:The doped semiconductor given in the diagram is a p-type semiconductor. It means the dopant element must have less valence electron than germanium.

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Chapter 12 Solutions

CHEMISTRY THE CENTRAL SCIENCE >EBOOK<

Ch. 12 - Prob. 2ECh. 12 - Prob. 3ECh. 12 - Prob. 4ECh. 12 - Prob. 5ECh. 12 - Prob. 6ECh. 12 - Prob. 7ECh. 12 - Prob. 8ECh. 12 - Prob. 9ECh. 12 - Prob. 10ECh. 12 - 12.11 Covalent bonding occurs in both molecular...Ch. 12 - Prob. 12ECh. 12 - 12.13 What kinds of attractive forces exist...Ch. 12 - Prob. 14ECh. 12 - Prob. 15ECh. 12 - Prob. 16ECh. 12 - Prob. 17ECh. 12 - Prob. 18ECh. 12 - Prob. 19ECh. 12 - Amorphous silica, SiO2, has a density of about...Ch. 12 - Two patterns of packing for two different circles...Ch. 12 - Prob. 22ECh. 12 - Prob. 23ECh. 12 - Prob. 24ECh. 12 - Which of the three-dimensional primitive lattices...Ch. 12 - Prob. 26ECh. 12 - 12.27 What is the minimum number of atoms that...Ch. 12 - 12.28 What is the minimum number of atoms that...Ch. 12 - Prob. 29ECh. 12 - Prob. 30ECh. 12 - Prob. 31ECh. 12 - Prob. 32ECh. 12 - Prob. 33ECh. 12 - Prob. 34ECh. 12 - Prob. 35ECh. 12 - Prob. 36ECh. 12 - Prob. 37ECh. 12 - Prob. 38ECh. 12 - Prob. 39ECh. 12 - Prob. 40ECh. 12 - Prob. 41ECh. 12 - Prob. 42ECh. 12 - Prob. 43ECh. 12 - Prob. 44ECh. 12 - Prob. 45ECh. 12 - Prob. 46ECh. 12 - Prob. 47ECh. 12 - Prob. 48ECh. 12 - Prob. 49ECh. 12 - Prob. 50ECh. 12 - Prob. 51ECh. 12 - Prob. 52ECh. 12 - 12.53 Which would you expect to be the more...Ch. 12 - 12.54 Which of the following statements does not...Ch. 12 - Prob. 55ECh. 12 - Prob. 56ECh. 12 - Prob. 57ECh. 12 - Prob. 58ECh. 12 - Prob. 59ECh. 12 - Prob. 60ECh. 12 - 12.61 A particular form of cinnabar (HgS) adopts...Ch. 12 - At room temperature and pressure RbI crystallizes...Ch. 12 - Prob. 63ECh. 12 - Prob. 64ECh. 12 - The coordination number for Mg2+ ion is usually...Ch. 12 - Prob. 66ECh. 12 - Prob. 67ECh. 12 - Prob. 68ECh. 12 - Prob. 69ECh. 12 - Prob. 70ECh. 12 - Prob. 71ECh. 12 - Prob. 72ECh. 12 - Prob. 73ECh. 12 - Prob. 74ECh. 12 - Prob. 75ECh. 12 - Prob. 76ECh. 12 - Prob. 77ECh. 12 - Prob. 78ECh. 12 - Prob. 79ECh. 12 - Prob. 80ECh. 12 - Prob. 81ECh. 12 - Prob. 82ECh. 12 - Prob. 83ECh. 12 - Prob. 84ECh. 12 - Prob. 85ECh. 12 - 12.86 Write a balanced chemical equation for the...Ch. 12 - Prob. 87ECh. 12 - Prob. 88ECh. 12 - Prob. 89ECh. 12 - Prob. 90ECh. 12 - Prob. 91ECh. 12 - Prob. 92ECh. 12 - Prob. 93ECh. 12 - Prob. 94ECh. 12 - Explain why “bands” may not be the most accurate...Ch. 12 - Prob. 96ECh. 12 - Prob. 97ECh. 12 - Prob. 98ECh. 12 - Prob. 99ECh. 12 - An ideal quantum dot for use in TVs does not...Ch. 12 - Prob. 101ECh. 12 - Prob. 102ECh. 12 - Prob. 103AECh. 12 - Prob. 104AECh. 12 - Prob. 105AECh. 12 - Pure iron crystallizes in a body-centered cubic...Ch. 12 - Prob. 107AECh. 12 - Prob. 108AECh. 12 - Prob. 109AECh. 12 - What type of latticeprimitive cubic, body-centered...Ch. 12 - Prob. 111AECh. 12 - Prob. 112AECh. 12 - Prob. 113AECh. 12 - Energy bands are considered continuous due to the...Ch. 12 - Prob. 115AECh. 12 - Prob. 116AECh. 12 - Prob. 117AECh. 12 - Prob. 118AECh. 12 - Prob. 119AECh. 12 - Prob. 120AECh. 12 - Prob. 121AECh. 12 - Prob. 122AECh. 12 - Prob. 123AECh. 12 - The karat scale used to describe gold alloys is...Ch. 12 - 12.125 Spinel is a mineral that contains 37.9% AI,...Ch. 12 - Prob. 126IECh. 12 - Prob. 127IECh. 12 - Prob. 128IECh. 12 - Prob. 129IECh. 12 - Silicon has the diamond structure with a unit cell...Ch. 12 - Prob. 131IECh. 12 - Prob. 132IE
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