Explanation 1) Concept: Using the equation for equilibrium of force and the equation of equilibrium of torque, we can solve for the distance of a crosspiece. 2) Equations: i) At equilibrium, F n e t = 0 ii) At equilibrium, τ n e t = 0 3) Given: i) The length of a beam is L. ii) The load of the beam is equally divided by three men. 4) Calculations: F W F We have given that the load of the beam is equally divided by three men. Suppose, one man is applying upward force F. At equilibrium, F n e t = 0 So, W = 3 × F … … … …

Fundamentals of Physics, Volume 1, Chapter 1-20

10th Edition

ISBN: 9781118233764

Author: David Halliday

Publisher: WILEY

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Center of Gravity of a system

The centre of gravity is a property that is based on the geometry of a rigid body or any particle. It is described as an equilibrium point or a hypothetical location where the total weight of the body is concentrated.

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Chapter 12, Problem 81P

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the distance of the crosspiece from the free end of the beam.

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Chapter 12, Problem 80P

Chapter 12, Problem 82P

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Chapter 12 Solutions

Fundamentals of Physics, Volume 1, Chapter 1-20

Ch. 12 - Figure 12-15 shows three situations in which the...Ch. 12 - In Fig, 12-16, a rigid beam is attached to two...Ch. 12 - Figure 12-17 shows four overhead views of rotating...Ch. 12 - A ladder leans against a frictionless wall but is...Ch. 12 - Figure 12-18 shows a mobile of toy penguins...Ch. 12 - Figure 12-19 shows an overhead view of a uniform...Ch. 12 - In Fig. 12-20, a stationary 5 kg rod AC is held...Ch. 12 - Three piatas hang from the stationary assembly of...Ch. 12 - In Fig. 12-22, a vertical rend is hinged at its...Ch. 12 - Figure 12-23 shows a horizontal block that is...

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the distance of the crosspiece from the free end of the beam.

Solution Summary: The author explains how to find the distance of a crosspiece from the free end of the beam.

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To find: the distance of the crosspiece from the free end of the beam.

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Chapter 12 Solutions

To find:

the distance of the crosspiece from the free end of the beam.