Explanation Formula used: Parabola with vertex at ( h , k ) ; Axis of symmetry parallel to a coordinate axis a > 0 . Vertex Focus Directrix Equation Axis of symmetry Opens ( h , k ) ( h + a , k ) x = h − a ( y − k ) 2 = 4 a ( x − h ) Parallel to x -axis Right ( h , k ) ( h − a , k ) x = h + a ( y − k ) 2 = − 4 a ( x − h ) Parallel to x -axis Left ( h , k ) ( h , k + a ) y = k − a ( x − h ) 2 = 4 a ( y − k ) Parallel to y -axis Up ( h , k ) ( h , k − a ) y = k + a ( x − h ) 2 = − 4 a ( y − k ) Parallel to y -axis Down Calculation: The equation of the parabola is, ( y + 2 ) 2 = 4 ( x + 1 ) . Rewrite the equation as ( y − 2 ) 2 = 4 ( x − 1 ) . Note that the equation is of the form ( y − k ) 2 = 4 a ( x − h ) which opens right with vertex at ( h , k ) , focus at ( h + a , k ) , and directrix x = h − a

4th Edition

ISBN: 9780134556079

Author: Sullivan, Michael, III, Struve, Katherine R., Mazzarella, Janet.

Publisher: Pearson,

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Chapter 12, Problem 7T

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The vertex, focus, directrix of the parabola (y+2)2=4(x+1) and graph the same.

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Chapter 12, Problem 6T

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The vertex, focus, directrix of the parabola ( y + 2 ) 2 = 4 ( x + 1 ) and graph the same.

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The vertex, focus, directrix of the parabola (y+2)2=4(x+1) and graph the same.

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