Interpretation Introduction To determine: The freezing point and the boiling point of the solution. Explanation Given: Mass of naphthalene ( m n ) is 10 g . Volume of benzene ( V ) is 100 mL . Density of benzene ( ρ ) is 0 .877 g / c m 3 = 0 .877 g / mL . Explanation: Boiling point of benzene ( T pure ) is 80.1 ∘ C . Freezing point of benzene ( T pure ) is 5.5 ∘ C . Molar mass of naphthalene ( MM n ) is 128.171 g / mol . The density of a solution is equal to the ratio of the mass and volume of solution. Here, mass of benzene can be calculated as m w = ρ × V where m b is the mass of benzene, ρ is the density of benzene, and V is the volume of benzene. Substitute 0 .877 g / mL for ρ and 100 mL for V : m w = 0 .877 g / mL × 100 mL = 87.7 g Mass of benzene is 87.7 g . One gram is equal to 10 − 3 kilograms. Convert grams to kilograms as follows: 87.7 g = 87.7 g × ( 10 − 3 kg 1 g ) = 0.0877 kg Mass of benzene in kilograms is 0.0877 kg . Calculate the number of moles of naphthalene as follows: n n = m n MM n Here, m n is the given mass of naphthalene and MM n is the molar mass of naphthalene. Substitute 10 g for m n and 128.171 g / mol for MM n : n n = 10 g 128.171 g / mol = 0.078 mol So, the number of moles of naphthalene is 0.078 mol . Molality of a solution ( m ) is equal to the ratio of the number of moles of solute (naphthalene) and mass of solvent (benzene) in kilograms. m = n n m b Substitute 0.0877 kg for m b and 0.078 mol for n n : m = 0.078 mol 0.0877 kg = 0.889 m So, the molality of the solution is 0

Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Principles Of Chemistry: A Molecular Approach

3rd Edition

ISBN: 9780133890686

Author: Tro

Publisher: PEARSON

See similar textbooks

Concept explainers

Solutions

Solutions can be considered as homogeneous mixtures which contain two or more than two chemical substances. The chemical substance which is the greater part is defined as solvent. And the chemical substance that is dissolved in a solvent is referred to a…

Videos

Question

Chapter 12, Problem 79E

Interpretation Introduction

To determine: The freezing point and the boiling point of the solution.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 12, Problem 78E

Chapter 12, Problem 80E

Students have asked these similar questions

Electrochemistry. Briefly describe the Donnan potential.

Indicate what the Luther equation is used for?

Indicate one aspect that benefits and another that makes it difficult to use the hydroquinone electrode to measure pH.

Chapter 12 Solutions

Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Principles Of Chemistry: A Molecular Approach

Ch. 12 - Prob. 1SAQ Ch. 12 - Prob. 2SAQ Ch. 12 - Q3. A 500.0-mL sample of pure water is allowed to...Ch. 12 - Q4. A potassium bromide solution is 7.55 %...Ch. 12 - Prob. 5SAQ Ch. 12 - Prob. 6SAQ Ch. 12 - Prob. 7SAQ Ch. 12 - Prob. 8SAQ Ch. 12 - Prob. 9SAQ Ch. 12 - Prob. 10SAQ

Ch. 12 - Prob. 11SAQ Ch. 12 - Q12. The enthalpy of solution for NaOH is –44.46...Ch. 12 - Q13. A 2.4 m aqueous solution of an ionic compound...Ch. 12 - Q14. A solution is an equimolar mixture of two...Ch. 12 - Prob. 15SAQ Ch. 12 - Prob. 1E Ch. 12 - Prob. 2E Ch. 12 - Prob. 3E Ch. 12 - Prob. 4E Ch. 12 - Prob. 5E Ch. 12 - Prob. 6E Ch. 12 - Prob. 7E Ch. 12 - Prob. 8E Ch. 12 - Prob. 9E Ch. 12 - 10. What is the heat of hydration (ΔHhydration)?...Ch. 12 - Prob. 11E Ch. 12 - Prob. 12E Ch. 12 - Prob. 13E Ch. 12 - Prob. 14E Ch. 12 - Prob. 15E Ch. 12 - Prob. 16E Ch. 12 - Prob. 17E Ch. 12 - Prob. 18E Ch. 12 - Prob. 19E Ch. 12 - Prob. 20E Ch. 12 - Prob. 21E Ch. 12 - 22. Explain why the lower vapor pressure for a...Ch. 12 - Prob. 23E Ch. 12 - Prob. 24E Ch. 12 - Prob. 25E Ch. 12 - Prob. 26E Ch. 12 - Prob. 27E Ch. 12 - Prob. 28E Ch. 12 - Prob. 29E Ch. 12 - 30. Pick an appropriate solvent from Table 13.3 to...Ch. 12 - 31. Which molecule would you expect to be more...Ch. 12 - 32. Which molecule would you expect to be more...Ch. 12 - Prob. 33E Ch. 12 - Prob. 34E Ch. 12 - 35. When ammonium chloride (NH4Cl) is dissolved in...Ch. 12 - 36. When lithium iodide (LiI) is dissolved in...Ch. 12 - Silver nitrate has a lattice energy of 820 kJ/mol...Ch. 12 - Prob. 38E Ch. 12 - Prob. 39E Ch. 12 - Prob. 40E Ch. 12 - Prob. 41E Ch. 12 - 42. A solution contains 32 g of KNO3 per 100.0 g...Ch. 12 - Prob. 43E Ch. 12 - Prob. 44E Ch. 12 - Prob. 45E Ch. 12 - Prob. 46E Ch. 12 - Prob. 47E Ch. 12 - Prob. 48E Ch. 12 - Prob. 49E Ch. 12 - Prob. 50E Ch. 12 - Prob. 51E Ch. 12 - Prob. 52E Ch. 12 - Prob. 53E Ch. 12 - Prob. 54E Ch. 12 - 55. Silver nitrate solutions are often used to...Ch. 12 - Prob. 56E Ch. 12 - Prob. 57E Ch. 12 - Prob. 58E Ch. 12 - Prob. 59E Ch. 12 - Prob. 60E Ch. 12 - Prob. 61E Ch. 12 - Prob. 62E Ch. 12 - Prob. 63E Ch. 12 - Prob. 64E Ch. 12 - Prob. 65E Ch. 12 - Prob. 66E Ch. 12 - Prob. 67E Ch. 12 - Prob. 68E Ch. 12 - Prob. 69E Ch. 12 - Prob. 70E Ch. 12 - 71. Calculate the vapor pressure of a solution...Ch. 12 - Prob. 72E Ch. 12 - 73. A solution contains 50.0 g of heptane (C7H16)...Ch. 12 - Prob. 74E Ch. 12 - 75. A solution contains 4.08 g of chloroform...Ch. 12 - Prob. 76E Ch. 12 - Prob. 77E Ch. 12 - Prob. 78E Ch. 12 - 79. Calculate the freezing point and boiling point...Ch. 12 - 80. Calculate the freezing point and boiling...Ch. 12 - 81. An aqueous solution containing 17.5 g of an...Ch. 12 - Prob. 82E Ch. 12 - 83. Calculate the osmotic pressure of a solution...Ch. 12 - Prob. 84E Ch. 12 - 85. A solution containing 27.55 mg of an unknown...Ch. 12 - Prob. 86E Ch. 12 - 87. Calculate the freezing point and boiling point...Ch. 12 - Prob. 88E Ch. 12 - Prob. 89E Ch. 12 - Prob. 90E Ch. 12 - Prob. 91E Ch. 12 - Prob. 92E Ch. 12 - Prob. 93E Ch. 12 - Prob. 94E Ch. 12 - 95. A 0.100 M ionic solution has an osmotic...Ch. 12 - Prob. 96E Ch. 12 - 97. Calculate the vapor pressure at 25 °C of an...Ch. 12 - Prob. 98E Ch. 12 - Prob. 99E Ch. 12 - 100. The solubility of phenol in water at 25 °C is...Ch. 12 - Prob. 101E Ch. 12 - Prob. 102E Ch. 12 - Prob. 103E Ch. 12 - Prob. 104E Ch. 12 - Prob. 105E Ch. 12 - Prob. 106E Ch. 12 - Prob. 107E Ch. 12 - 108. The vapor above an aqueous solution contains...Ch. 12 - Prob. 109E Ch. 12 - Prob. 110E Ch. 12 - Prob. 111E Ch. 12 - Prob. 112E Ch. 12 - Prob. 113E Ch. 12 - Prob. 114E Ch. 12 - Prob. 115E Ch. 12 - Prob. 116E Ch. 12 - Prob. 117E Ch. 12 - Prob. 118E Ch. 12 - Prob. 119E Ch. 12 - Prob. 120E Ch. 12 - Prob. 121E Ch. 12 - Prob. 122E Ch. 12 - 123. A 100.0-mL aqueous sodium chloride solution...Ch. 12 - Prob. 124E Ch. 12 - Prob. 125E Ch. 12 - Prob. 126E Ch. 12 - 127. A 1.10-g sample contains only glucose...Ch. 12 - 128. A solution is prepared by mixing 631 mL of...Ch. 12 - 129. Two alcohols, isopropyl alcohol and propyl...Ch. 12 - Prob. 130E Ch. 12 - Prob. 131E Ch. 12 - 132. A solution of 75.0 g of benzene (C6H6) and...Ch. 12 - Prob. 133E Ch. 12 - Prob. 134E Ch. 12 - Prob. 135E Ch. 12 - Prob. 136E Ch. 12 - 137. If each substance listed here costs the same...Ch. 12 - Prob. 138E

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.