EBK ESSENTIAL STATISTICS FOR THE BEHAVI
2nd Edition
ISBN: 9781506386287
Author: PRIVITERA
Publisher: VST
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Chapter 12, Problem 6FP
To determine
To explain: The pattern of the graph of
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30. An individual who has automobile insurance from a certain company is randomly selected. Let Y be the num- ber of moving violations for which the individual was cited during the last 3 years. The pmf of Y isy | 1 2 4 8 16p(y) | .05 .10 .35 .40 .10
a.Compute E(Y).b. Suppose an individual with Y violations incurs a surcharge of $100Y^2. Calculate the expected amount of the surcharge.
24. An insurance company offers its policyholders a num- ber of different premium payment options. For a ran- domly selected policyholder, let X = the number of months between successive payments. The cdf of X is as follows:
F(x)=0.00 : x < 10.30 : 1≤x<30.40 : 3≤ x < 40.45 : 4≤ x <60.60 : 6≤ x < 121.00 : 12≤ x
a. What is the pmf of X?b. Using just the cdf, compute P(3≤ X ≤6) and P(4≤ X).
59. At a certain gas station, 40% of the customers use regular gas (A1), 35% use plus gas (A2), and 25% use premium (A3). Of those customers using regular gas, only 30% fill their tanks (event B). Of those customers using plus, 60% fill their tanks, whereas of those using premium, 50% fill their tanks.a. What is the probability that the next customer will request plus gas and fill the tank (A2 B)?b. What is the probability that the next customer fills the tank?c. If the next customer fills the tank, what is the probability that regular gas is requested? Plus? Premium?
Chapter 12 Solutions
EBK ESSENTIAL STATISTICS FOR THE BEHAVI
Ch. 12 - Prob. 1FPCh. 12 - Prob. 2FPCh. 12 - Prob. 3FPCh. 12 - Prob. 4FPCh. 12 - Prob. 5FPCh. 12 - Prob. 6FPCh. 12 - Prob. 7FPCh. 12 - Prob. 8FPCh. 12 - Prob. 9FPCh. 12 - Prob. 10FP
Ch. 12 - Prob. 11FPCh. 12 - Prob. 12FPCh. 12 - Prob. 13CAPCh. 12 - Prob. 14CAPCh. 12 - Prob. 15CAPCh. 12 - Prob. 16CAPCh. 12 - Prob. 17CAPCh. 12 - Prob. 18CAPCh. 12 - Prob. 19CAPCh. 12 - Prob. 20CAPCh. 12 - Prob. 21CAPCh. 12 - Prob. 22CAPCh. 12 - Prob. 23CAPCh. 12 - Prob. 24CAPCh. 12 - Prob. 25CAPCh. 12 - Prob. 26CAPCh. 12 - Prob. 27CAPCh. 12 - Prob. 28CAPCh. 12 - Prob. 29PRCh. 12 - Prob. 30PRCh. 12 - Prob. 31PRCh. 12 - Prob. 32PR
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- 20 km, because GISS Worksheet 10 Jesse runs a small business selling and delivering mealie meal to the spaza shops. He charges a fixed rate of R80, 00 for delivery and then R15, 50 for each packet of mealle meal he delivers. The table below helps him to calculate what to charge his customers. 10 20 30 40 50 Packets of mealie meal (m) Total costs in Rands 80 235 390 545 700 855 (c) 10.1. Define the following terms: 10.1.1. Independent Variables 10.1.2. Dependent Variables 10.2. 10.3. 10.4. 10.5. Determine the independent and dependent variables. Are the variables in this scenario discrete or continuous values? Explain What shape do you expect the graph to be? Why? Draw a graph on the graph provided to represent the information in the table above. TOTAL COST OF PACKETS OF MEALIE MEAL 900 800 700 600 COST (R) 500 400 300 200 100 0 10 20 30 40 60 NUMBER OF PACKETS OF MEALIE MEALarrow_forwardLet X be a random variable with support SX = {−3, 0.5, 3, −2.5, 3.5}. Part ofits probability mass function (PMF) is given bypX(−3) = 0.15, pX(−2.5) = 0.3, pX(3) = 0.2, pX(3.5) = 0.15.(a) Find pX(0.5).(b) Find the cumulative distribution function (CDF), FX(x), of X.1(c) Sketch the graph of FX(x).arrow_forwardA well-known company predominantly makes flat pack furniture for students. Variability with the automated machinery means the wood components are cut with a standard deviation in length of 0.45 mm. After they are cut the components are measured. If their length is more than 1.2 mm from the required length, the components are rejected. a) Calculate the percentage of components that get rejected. b) In a manufacturing run of 1000 units, how many are expected to be rejected? c) The company wishes to install more accurate equipment in order to reduce the rejection rate by one-half, using the same ±1.2mm rejection criterion. Calculate the maximum acceptable standard deviation of the new process.arrow_forward
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