CHEMISTRY IN FOCUS W/ OWL (LL)>IP<
CHEMISTRY IN FOCUS W/ OWL (LL)>IP<
6th Edition
ISBN: 9781337306317
Author: Tro
Publisher: CENGAGE L
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Chapter 12, Problem 56E
Interpretation Introduction

Interpretation:

The reason for the disappearance of solid CO2 directly to gas, without coming into molten form is to be explained.

Concept Introduction:

Solid, liquid and gas are the three states of the matter. Their existence depends on the prevailing intermolecular forces. If the forces are very strong, the molecule exists as a solid at room temperature.

When these forces start decreasing, the state changes from solid to liquid. This is termed as melting. On further decrease in the intermolecular forces, liquid changes to a gas. This is termed as vaporization. Some substances bypass the liquid state and directly convert from solid state to gaseous state. This process is known as sublimation.

There is a number of intermolecular forces which play a role in different molecules such as dipole-dipole, hydrogen bonding, and dispersion forces.

The compounds lacking specific functional moieties have dispersion forces acting on their molecules. These increase with an increase in the molecular mass.

Lower are the forces of attraction, more is the volatility of the substance.

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13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…

Chapter 12 Solutions

CHEMISTRY IN FOCUS W/ OWL (LL)>IP<

Ch. 12 - A representation of liquid water is shown below....Ch. 12 - Prob. 3SCCh. 12 - Prob. 4SCCh. 12 - Prob. 1ECh. 12 - Prob. 2ECh. 12 - Prob. 3ECh. 12 - Prob. 4ECh. 12 - Prob. 5ECh. 12 - Prob. 6ECh. 12 - Prob. 7ECh. 12 - Prob. 8ECh. 12 - Prob. 9ECh. 12 - Prob. 10ECh. 12 - Why does sweating cool the human body?Ch. 12 - Prob. 12ECh. 12 - Prob. 13ECh. 12 - Prob. 14ECh. 12 - Explain the hydrologic cycle.Ch. 12 - Prob. 16ECh. 12 - Prob. 17ECh. 12 - How does a water softener work?Ch. 12 - Prob. 19ECh. 12 - Prob. 20ECh. 12 - Prob. 21ECh. 12 - What is the SDWA?Ch. 12 - Prob. 23ECh. 12 - Prob. 24ECh. 12 - Prob. 25ECh. 12 - Explain the concerns that groups like the EWG or...Ch. 12 - Prob. 27ECh. 12 - Prob. 28ECh. 12 - Which compound would you expect to have the...Ch. 12 - Which compound would you expect to have the...Ch. 12 - Prob. 31ECh. 12 - Prob. 32ECh. 12 - Classify each molecule as polar or nonpolar:...Ch. 12 - Classify each molecule as polar or nonpolar:...Ch. 12 - Prob. 35ECh. 12 - Prob. 36ECh. 12 - Prob. 37ECh. 12 - Prob. 38ECh. 12 - How many grams of sucrose (C12H22O11) are present...Ch. 12 - How many grams of glucose (C6H12O6) are present in...Ch. 12 - Prob. 41ECh. 12 - How many grams of NaF are present in 4.5 L of a...Ch. 12 - A 250-g sample of hard water contains...Ch. 12 - Prob. 44ECh. 12 - Prob. 45ECh. 12 - Prob. 46ECh. 12 - Prob. 47ECh. 12 - Prob. 48ECh. 12 - Prob. 49ECh. 12 - Prob. 50ECh. 12 - Prob. 51ECh. 12 - Prob. 52ECh. 12 - Prob. 53ECh. 12 - Prob. 54ECh. 12 - Prob. 55ECh. 12 - Prob. 56ECh. 12 - Prob. 57ECh. 12 - Prob. 58E
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Solutions: Crash Course Chemistry #27; Author: Crash Course;https://www.youtube.com/watch?v=9h2f1Bjr0p4;License: Standard YouTube License, CC-BY