CHEMISTRY IN FOCUS W/ OWL (LL)>IP<
CHEMISTRY IN FOCUS W/ OWL (LL)>IP<
6th Edition
ISBN: 9781337306317
Author: Tro
Publisher: CENGAGE L
bartleby

Concept explainers

Question
Book Icon
Chapter 12, Problem 28E
Interpretation Introduction

Interpretation:

The molecule which exists as solid at room temperature is to be determined out of the four given options.

Concept Introduction:

A hydrocarbon is organic compound consisting entirely of hydrogen and carbon.

Butane and hexane both are hydrocarbon. Butane is a four-carbon alkane and hexane contains six carbon atoms.

The temperature at which the vapour pressure of the liquid is equal to the pressure exerted on the liquid by the surrounding atmosphere is called boiling point.

Boiling point of a molecule depends on the intermolecular forces and thermal energy.

Intermolecular forces are of two types: dispersion forces and dipole forces.

Dispersion forces are possessed by all the atoms or molecules, which depend on the molar mass.

Dipole forces exist between polar molecules, which depend on the polarity of the molecules.

Intermolecular forces keep the molecules together. Greater the intermolecular force, higher is the boiling point.

All atoms and molecules possess dispersion forces which depend upon their molar mass.

Polar molecules possess dipole forces between them which depend upon the polarity of the molecules.

A molecular formula consists of the chemical symbols for the constituent elements followed by numeric subscripts describing the number of atoms of each element present in the molecule.

Dispersion forces are weak intermolecular forces and are considered van der waals forces.

Temporary dipoles can occur in non-polar molecules when the electrons that constantly orbit the nucleus occupy a similar location by chance.

Higher the molar mass, higher is the magnitude of the dispersion forces, and hence, higher is the boiling point.

Molecules which have lower molar masses have lower dispersion forces because dispersion force is directly proportional to the molar mass.

Molecules which have higher molar masses have higher dispersion forces.

Blurred answer
Students have asked these similar questions
5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3
Show work. don't give Ai generated solution.  How many carbons and hydrogens are in the structure?
13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…

Chapter 12 Solutions

CHEMISTRY IN FOCUS W/ OWL (LL)>IP<

Ch. 12 - A representation of liquid water is shown below....Ch. 12 - Prob. 3SCCh. 12 - Prob. 4SCCh. 12 - Prob. 1ECh. 12 - Prob. 2ECh. 12 - Prob. 3ECh. 12 - Prob. 4ECh. 12 - Prob. 5ECh. 12 - Prob. 6ECh. 12 - Prob. 7ECh. 12 - Prob. 8ECh. 12 - Prob. 9ECh. 12 - Prob. 10ECh. 12 - Why does sweating cool the human body?Ch. 12 - Prob. 12ECh. 12 - Prob. 13ECh. 12 - Prob. 14ECh. 12 - Explain the hydrologic cycle.Ch. 12 - Prob. 16ECh. 12 - Prob. 17ECh. 12 - How does a water softener work?Ch. 12 - Prob. 19ECh. 12 - Prob. 20ECh. 12 - Prob. 21ECh. 12 - What is the SDWA?Ch. 12 - Prob. 23ECh. 12 - Prob. 24ECh. 12 - Prob. 25ECh. 12 - Explain the concerns that groups like the EWG or...Ch. 12 - Prob. 27ECh. 12 - Prob. 28ECh. 12 - Which compound would you expect to have the...Ch. 12 - Which compound would you expect to have the...Ch. 12 - Prob. 31ECh. 12 - Prob. 32ECh. 12 - Classify each molecule as polar or nonpolar:...Ch. 12 - Classify each molecule as polar or nonpolar:...Ch. 12 - Prob. 35ECh. 12 - Prob. 36ECh. 12 - Prob. 37ECh. 12 - Prob. 38ECh. 12 - How many grams of sucrose (C12H22O11) are present...Ch. 12 - How many grams of glucose (C6H12O6) are present in...Ch. 12 - Prob. 41ECh. 12 - How many grams of NaF are present in 4.5 L of a...Ch. 12 - A 250-g sample of hard water contains...Ch. 12 - Prob. 44ECh. 12 - Prob. 45ECh. 12 - Prob. 46ECh. 12 - Prob. 47ECh. 12 - Prob. 48ECh. 12 - Prob. 49ECh. 12 - Prob. 50ECh. 12 - Prob. 51ECh. 12 - Prob. 52ECh. 12 - Prob. 53ECh. 12 - Prob. 54ECh. 12 - Prob. 55ECh. 12 - Prob. 56ECh. 12 - Prob. 57ECh. 12 - Prob. 58E
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning
Text book image
Introductory Chemistry For Today
Chemistry
ISBN:9781285644561
Author:Seager
Publisher:Cengage
Text book image
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Text book image
Introductory Chemistry: A Foundation
Chemistry
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
World of Chemistry, 3rd edition
Chemistry
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Brooks / Cole / Cengage Learning
Text book image
Chemistry In Focus
Chemistry
ISBN:9781337399692
Author:Tro, Nivaldo J.
Publisher:Cengage Learning,