Explanation The universal gravitational constant is 6.67 × 10 − 11 N ⋅ m 2 / kg 2 , mass of the earth is 5.97 × 10 24 kg , radius of earth is 6.37 × 10 6 m . The formula for gravitational potential energy is, U = − G m M r Here, U is the gravitational potential energy m is mass of module M is mass of moon r is the distance between moon and the module G is the universal gravitational constant The formula for kinetic energy is, K = 1 2 m v 2 Here, K is the kinetic energy v is the velocity The formula for total energy is, E = U + K Here, E is the total energy of the system. Substitute 1 2 m v 2 for K and − G m M r for U in the above expression. E = − G m M r + 1 2 m v 2 For projectile at a height above surface of earth: Substitute E 1 for E , r 1 for r and v c for v in the above expression. E 1 = − G m M r 1 + 1 2 m v c 2 (1) Here, v c is the escape speed of the earth The expression for value of r 1 is, r 1 = r e + h Here, r e is the radius of earth h is the height of projectile from the surface of the earth The formula for escape speed is v c = 2 G M r e (2) Here, G is the universal gravitational constant M is the mass of earth r e is the radius of earth For projectile on surface of earth: Substitute E 2 for E , r e for r and v c 3 for v in the above expression

5th Edition

ISBN: 9780136782490

Author: Walker

Publisher: PEARSON CO

See similar textbooks

Concept explainers

Central Force

Central force is the force that acts along the center of mass of one body to the center of mass of another body. Its direction from or away from a point on a body to another is called the center of the force. Such forces include gravitational force betwe…

Question

Chapter 12, Problem 53PCE

To determine

The height above the earth at which speed of the projectile is one-third of the escape speed of the earth,

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 12, Problem 52PCE

Chapter 12, Problem 54PCE

Students have asked these similar questions

Part A m 2πkT ) 3/2 Calculate the integral (v) = f vƒ (v)dv. The function f(v) describing the actual distribution of molecular speeds is called the Maxwell-Boltzmann distribution, = ƒ(v) = 4π (· v²e-mv²/2kT . (Hint: Make the change of variable v² =x and use the tabulated integral foxne integer and a is a positive constant.) Express your answer in terms of the variables T, m, and appropriate constants. -ax dx n! - an+1 where n is a positive (v) = ΕΠΙ ΑΣΦ Submit Previous Answers Request Answer ? × Incorrect; Try Again; 4 attempts remaining Al Study Tools Looking for some guidance? Let's work through a few related practice questions before you go back to the real thing. This won't impact your score, so stop at anytime and ask for clarification whenever you need it. Ready to give it a try? Start

Starter the rule of significant

Please solve this problem and give step by step explanations on each step while breaking it down please. Thank you!!

Chapter 12 Solutions

EP PHYSICS -MOD.MASTERING (18W)

Ch. 12.1 - Rank the four systems shown in Figure 12-6 in...Ch. 12.2 - Suppose the Sun suddenly collapsed to half its...Ch. 12.3 - Satellite A orbits the Earth at the radius r,...Ch. 12.4 - Prob. 4EYU Ch. 12.5 - Prob. 5EYU Ch. 12.6 - If the radius of the Moons orbit around the Earth...Ch. 12 - It is often said that astronauts in orbit...Ch. 12 - When a person passes you on the street, you do not...Ch. 12 - Imagine bringing the tips of your index fingers...Ch. 12 - Does the radius vector of Mars sweep out the same...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.

The height above the earth at which speed of the projectile is one-third of the escape speed of the earth,

Solution Summary: The author explains the universal gravitational constant, mass of the earth, distance between moon and module, and the formula for kinetic energy.

Concept explainers

The height above the earth at which speed of the projectile is one-third of the escape speed of the earth,

Want to see the full answer?

Chapter 12 Solutions