
Concept explainers
(a)
Interpretation:
The Lewis structure of molecules or ions, spatial orientation of electron pairs and the simple geometric structure indicating the approximate bond angles of that molecules or ions should be determined.
Concept Introduction:
Lewis structure represents the valence electron arrangement around the atoms of the molecule. Lewis structure can be drawn for ionic or covalent bonds.
When predicting the geometric structure, VSPER theory is used. The three-dimensional structure of atoms in.

Answer to Problem 46CR
Explanation of Solution
For H2 O
Part A Step 1 →
Sum(total atoms)
Step 2 →
Pair of electrons =
Electron pairs for bonds =
Step 3 → Remaining electron pairs = 2
Part B Step 1 → Lewis structure
Step 2 → 4 electron pairs around
Step 3 → But around the
No: of bonding pairs =
No: of non- bonding pairs =
Step 4 → Name of the structure = V-shaped or Bend.
(b)
Interpretation:
The Lewis structure of molecules or ions, spatial orientation of electron pairs and the simple geometric structure indicating the approximate bond angles of that molecules or ions should be determined.
Concept Introduction:
Lewis structure represents the valence electron arrangement around the atoms of the molecule. Lewis structure can be drawn for ionic or covalent bonds.
When predicting the geometric structure, VSPER theory is used. The three-dimensional structure of atoms in.

Answer to Problem 46CR
Explanation of Solution
For PH3 Part A Step 1 →
Sum
Step 2 → Pair of electrons =
Electron pairs for bonds =
Step 3 → Remain electron pairs =
Part B Step 1 → Lewis structure
Step 2 →
Step 3 → But around the
No: of non- bonding pairs = 1
Step 4 → Name of the structure = Trigonal pyramid.
(c)
Interpretation:
The Lewis structure of molecules or ions, spatial orientation of electron pairs and the simple geometric structure indicating the approximate bond angles of that molecules or ions should be determined.
Concept Introduction:
Lewis structure represents the valence electron arrangement around the atoms of the molecule. Lewis structure can be drawn for ionic or covalent bonds.
When predicting the geometric structure, VSPER theory is used. The three-dimensional structure of atoms in.

Answer to Problem 46CR
Explanation of Solution
CBr4 Part A. Step 1 →
Sum = 32
Step 2 → Pair of electrons =
Electron pairs for bonds =
Step 3 → Remain electron pairs =
Part B Step 1 → Lewis structure
Step 2 →
Step 3 → But around the
No: of non- bonding pairs =
Step 4 → Name of the structure = Tetrahedral.
(d)
Interpretation:
The Lewis structure of molecules or ions, spatial orientation of electron pairs and the simple geometric structure indicating the approximate bond angles of that molecules or ions should be determined.
Concept Introduction:
Lewis structure represents the valence electron arrangement around the atoms of the molecule. Lewis structure can be drawn for ionic or covalent bonds.
When predicting the geometric structure, VSPER theory is used. The three-dimensional structure of atoms in.

Answer to Problem 46CR
Explanation of Solution
For ClO4 -
Part A. Step 1 →
Sum =
Step 2 → Pair of electrons =
Electron pairs for bonds =
Step 3 → Remain electron pairs =
Part B Step 1 → Lewis structure
Step 2 →
Step 3 → But around the
No: of non- bonding pairs =
Step 4 → Name of the structure = Tetrahedral
But considering resonance, the exact position of three p bonds cannot be determined exactly. It provides a p cloud over the molecule. So that a resonance hybrid determines the exact structure of ClO4 - molecule.
(e)
Interpretation:
The Lewis structure of molecules or ions, spatial orientation of electron pairs and the simple geometric structure indicating the approximate bond angles of that molecules or ions should be determined.
Concept Introduction:
Lewis structure represents the valence electron arrangement around the atoms of the molecule. Lewis structure can be drawn for ionic or covalent bonds.
When predicting the geometric structure, VSPER theory is used. The three-dimensional structure of atoms in.

Answer to Problem 46CR
Explanation of Solution
BF3
Part A. Step 1 →
Sum =
Step 2 → Pair of electrons =
Electron pairs for bonds =
Step 3 → Remain electron pairs =
Part B Step 1 → Lewis structure
Step 2 →
Step 3 → Also around the
No: of bonding pairs =
No: of non- bonding pairs =
Step 4 → Name of the structure = Trigonal planar.
(f)
Interpretation:
The Lewis structure of molecules or ions, spatial orientation of electron pairs and the simple geometric structure indicating the approximate bond angles of that molecules or ions should be determined.
Concept Introduction:
Lewis structure represents the valence electron arrangement around the atoms of the molecule. Lewis structure can be drawn for ionic or covalent bonds.
When predicting the geometric structure, VSPER theory is used. The three-dimensional structure of atoms in.

Answer to Problem 46CR
Explanation of Solution
BeF2
Part A. Step 1 →
Sum =
Step 2 → Pair of electrons =
Electron pairs for bonds =
Step 3 → Remain electron pairs =
Part B Step 1 → Lewis structure
Step 2 →
Step 3 → Also around the
No: of non- bonding pairs =
Step 4 → Name of the structure = Linear
.
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Chapter 12 Solutions
Student Solutions Manual for Zumdahl/DeCoste's Introductory Chemistry: A Foundation, 9th
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- 3-Oxo-butanenitrile and (E)-2-butenal are mixed with sodium ethoxide in ethanol. Draw and name the structures of the products.arrow_forwardWhat is the reason of the following(use equations if possible) a.) In MO preperation through diazotization: Addition of sodium nitrite in acidfied solution in order to form diazonium salt b.) in MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at low pH c.) In MO experiment: addition of sodium hydroxide solution in the last step to isolate the product MO. What is the color of MO at pH 4.5 d.) Avoiding not cooling down the reaction mixture when preparing the diazonium salt e.) Cbvcarrow_forwardA 0.552-g sample of an unknown acid was dissolved in water to a total volume of 20.0 mL. This sample was titrated with 0.1103 M KOH. The equivalence point occurred at 29.42 mL base added. The pH of the solution at 10.0 mL base added was 3.72. Determine the molar mass of the acid. Determine the Ka of the acid.arrow_forward
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