Loose Leaf for Statistical Techniques in Business and Economics
17th Edition
ISBN: 9781260152647
Author: Douglas A. Lind
Publisher: McGraw-Hill Education
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Chapter 12, Problem 3E
To determine
Obtain a difference in the variation of the two populations with significance level 0.02.
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32. Consider a normally distributed population with mean μ = 80
and standard deviation σ = 14.
a.
Construct the centerline and the upper and lower control
limits for the chart if samples of size 5 are used.
b. Repeat the analysis with samples of size 10.
2080 101
c. Discuss the effect of the sample size on the control limits.
Consider the following hypothesis test.
The following results are for two independent samples taken from the two populations.
Sample 1
Sample 2
n 1 = 80
n 2 = 70
x 1 = 104
x 2 = 106
σ 1 = 8.4
σ 2 = 7.6
What is the value of the test statistic? If required enter negative values as negative numbers (to 2 decimals).
What is the p-value (to 4 decimals)? Use z-table.
With = .05, what is your hypothesis testing conclusion?
Periodically, Merrill Lynch customers are asked to evaluate Merrill Lynch financial consultants and services (2000 Merrill Lynch Client Satisfaction Survey). Higher ratings on the client satisfaction survey indicate better service with 7 the maximum service rating. Independent samples of service ratings for two financial consultants are summarized here. Consultant A has 10 years of experience, whereas consultant B has 1 year of experience. Use = .05 and test to see whether the consultant with more experience has the higher population mean service rating.
Consultant A
Consultant B
= 16
= 10
= 6.82
= 6.25
= .64
= .75
State the null and alternative hypotheses.H0: 1 - 2 Ha: 1 - 2
Compute the value of the test statistic (to 2 decimals).
What is the p-value?The p-value is
What is your conclusion?
Chapter 12 Solutions
Loose Leaf for Statistical Techniques in Business and Economics
Ch. 12 - Steele Electric Products Inc. assembles cell...Ch. 12 - What is the critical F value when the sample size...Ch. 12 - Prob. 2ECh. 12 - Prob. 3ECh. 12 - Prob. 4ECh. 12 - Prob. 5ECh. 12 - Prob. 6ECh. 12 - Prob. 2SRCh. 12 - Prob. 7ECh. 12 - Prob. 8E
Ch. 12 - Prob. 9ECh. 12 - Prob. 10ECh. 12 - Prob. 3SRCh. 12 - Prob. 11ECh. 12 - The following are six observations collected from...Ch. 12 - Prob. 13ECh. 12 - Prob. 14ECh. 12 - Prob. 4SRCh. 12 - Prob. 15ECh. 12 - For exercises 15 and 16, conduct a test of...Ch. 12 - Prob. 17ECh. 12 - Prob. 18ECh. 12 - Prob. 5SRCh. 12 - Prob. 19ECh. 12 - Prob. 20ECh. 12 - Prob. 21ECh. 12 - Prob. 22ECh. 12 - Prob. 23CECh. 12 - Prob. 24CECh. 12 - Prob. 25CECh. 12 - Prob. 26CECh. 12 - In an ANOVA table, the MSE is equal to 10. Random...Ch. 12 - Prob. 28CECh. 12 - Prob. 29CECh. 12 - Prob. 30CECh. 12 - Prob. 31CECh. 12 - Prob. 32CECh. 12 - Prob. 33CECh. 12 - Prob. 34CECh. 12 - Prob. 35CECh. 12 - Prob. 36CECh. 12 - Prob. 37CECh. 12 - Prob. 38CECh. 12 - Shanks Inc., a nationwide advertising firm, wants...Ch. 12 - Prob. 40CECh. 12 - Prob. 41CECh. 12 - Prob. 42CECh. 12 - Prob. 43CECh. 12 - Prob. 44CECh. 12 - Prob. 45CECh. 12 - Prob. 46CECh. 12 - Prob. 47CECh. 12 - Prob. 48CECh. 12 - Prob. 50DACh. 12 - Prob. 51DACh. 12 - Prob. 1PCh. 12 - Prob. 2PCh. 12 - Prob. 3PCh. 12 - Prob. 4PCh. 12 - Prob. 5PCh. 12 - Prob. 6PCh. 12 - Prob. 7PCh. 12 - Prob. 1CCh. 12 - Prob. 2CCh. 12 - Prob. 1.1PTCh. 12 - The likelihood of rejecting a true null hypothesis...Ch. 12 - Prob. 1.3PTCh. 12 - Prob. 1.4PTCh. 12 - Prob. 1.5PTCh. 12 - Prob. 1.6PTCh. 12 - In a two-tailed test, the rejection region is...Ch. 12 - Prob. 1.8PTCh. 12 - Prob. 1.9PTCh. 12 - Prob. 1.10PTCh. 12 - Prob. 2.1PTCh. 12 - Prob. 2.2PTCh. 12 - Prob. 2.3PT
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