The dot product of two vectors x → = [ x 1 x 2 ⋮ x n ] and y → = [ y 1 y 2 ⋮ y n ] in ℝ ″ is defined by x → ⋅ y → = x 1 y 1 + x 2 y 2 + ⋯ + x n y n .Note that the dot product of two vectors is a scalar.We say that the vectors x → and y → are perpendicular if x → ⋅ y → = 0 . Find all vectors in ℝ 3 perpendicular to [ 1 3 − 1 ] . Draw a sketch.
The dot product of two vectors x → = [ x 1 x 2 ⋮ x n ] and y → = [ y 1 y 2 ⋮ y n ] in ℝ ″ is defined by x → ⋅ y → = x 1 y 1 + x 2 y 2 + ⋯ + x n y n .Note that the dot product of two vectors is a scalar.We say that the vectors x → and y → are perpendicular if x → ⋅ y → = 0 . Find all vectors in ℝ 3 perpendicular to [ 1 3 − 1 ] . Draw a sketch.
Solution Summary: The author explains that the subspace spanned by R3 is perpendicular to the vector
The dot product of two vectors
x
→
=
[
x
1
x
2
⋮
x
n
]
and
y
→
=
[
y
1
y
2
⋮
y
n
]
in
ℝ
″
is defined by
x
→
⋅
y
→
=
x
1
y
1
+
x
2
y
2
+
⋯
+
x
n
y
n
.Note that the dot product of two vectors is a scalar.We say that the vectors
x
→
and
y
→
are perpendicular if
x
→
⋅
y
→
=
0
.
Find all vectors in
ℝ
3
perpendicular to
[
1
3
−
1
]
.
Draw a sketch.
Quantities that have magnitude and direction but not position. Some examples of vectors are velocity, displacement, acceleration, and force. They are sometimes called Euclidean or spatial vectors.
Solve the system of equation for y using Cramer's rule. Hint: The
determinant of the coefficient matrix is -23.
-
5x + y − z = −7
2x-y-2z = 6
3x+2z-7
eric
pez
Xte
in
z=
Therefore, we have
(x, y, z)=(3.0000,
83.6.1 Exercise
Gauss-Seidel iteration with
Start with (x, y, z) = (0, 0, 0). Use the convergent Jacobi i
Tol=10 to solve the following systems:
1.
5x-y+z = 10
2x-8y-z=11
-x+y+4z=3
iteration (x
Assi 2
Assi 3.
4.
x-5y-z=-8
4x-y- z=13
2x - y-6z=-2
4x y + z = 7
4x-8y + z = -21
-2x+ y +5z = 15
4x + y - z=13
2x - y-6z=-2
x-5y- z=-8
realme Shot on realme C30
2025.01.31 22:35
f
Use Pascal's triangle to expand the binomial
(6m+2)^2
Chapter 1 Solutions
Linear Algebra With Applications (classic Version)
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