The major product obtained on treating the compounds in problem 29 with Br 2 at 125 ° C should be identified. Concept introduction: Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical. Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength. Bromination: 1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Question

Want to see the full answer?

Answer 1

Question

Chapter 12, Problem 30P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Using reaction free energy to predict equilibrium composition Consider the following equilibrium: 2NO2 (g) = N2O4(g) AGº = -5.4 kJ Now suppose a reaction vessel is filled with 4.53 atm of dinitrogen tetroxide (N2O4) at 279. °C. Answer the following questions about this system: Under these conditions, will the pressure of N2O4 tend to rise or fall? Is it possible to reverse this tendency by adding NO2? In other words, if you said the pressure of N2O4 will tend to rise, can that be changed to a tendency to fall by adding NO2? Similarly, if you said the pressure of N2O4 will tend to fall, can that be changed to a tendency to '2' rise by adding NO2? If you said the tendency can be reversed in the second question, calculate the minimum pressure of NO 2 needed to reverse it. Round your answer to 2 significant digits. 00 rise ☐ x10 fall yes no ☐ atm G Ar 1

Why do we analyse salt?

Curved arrows are used to illustrate the flow of electrons. Using the provided starting and product structures, draw the curved electron-pushing arrows for the following reaction or mechanistic step(s). Be sure to account for all bond-breaking and bond-making steps. H H CH3OH, H+ H Select to Add Arrows H° 0:0 'H + Q HH ■ Select to Add Arrows CH3OH, H* H. H CH3OH, H+ HH ■ Select to Add Arrows i Please select a drawing or reagent from the question area

Answer 2

Question

Chapter 12, Problem 30P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 3

Question

Chapter 12, Problem 30P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 4

Question

Chapter 12, Problem 30P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 5

Chapter 12, Problem 30P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 6

Chapter 12, Problem 30P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 7

Chapter 12, Problem 30P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 8

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 9

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 10

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 11

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

Want to see the full answer?

Check out a sample textbook solution

See solution

Answer 15

Ch. 12.2 - Prob. 1P Ch. 12.2 - Write the steps for formation of...Ch. 12.3 - Prob. 3P Ch. 12.4 - How many alkyl chlorides are obtained from...Ch. 12.4 - Prob. 6P Ch. 12.5 - Prob. 8P Ch. 12.5 - a. Would chlorination or bromination produce a...Ch. 12.5 - Show how the following compounds could be prepared...Ch. 12.6 - Prob. 12P Ch. 12.7 - Prob. 13P

Solution Summary: The author explains that the major product obtained on treating the compounds in problem 29 should be identified.

Concept explainers

Want to see the full answer?

Chapter 12 Solutions