The major product obtained on treating the compounds in problem 29 with Br 2 at 125 ° C should be identified. Concept introduction: Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical. Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength. Bromination: 1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

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Answer 1

Question

Chapter 12, Problem 30P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

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Answer 2

Question

Chapter 12, Problem 30P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

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Answer 3

Question

Chapter 12, Problem 30P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

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Answer 4

Question

Chapter 12, Problem 30P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

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Answer 5

Chapter 12, Problem 30P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 6

Chapter 12, Problem 30P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 7

Chapter 12, Problem 30P

(a)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methyl cyclohexane is undergoes radical bromination which forms 1-bromo-1-methyl cyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 8

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 9

(b)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 10

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 11

(c)

Interpretation Introduction

Interpretation:

The major product obtained on treating the compounds in problem 29 with Br2 at 125°C should be identified.

Concept introduction:

Radical or free radical: unpaired valence electron of an atom, molecule, or ion is called as radical.

Bond strength is depends on the formation of the radical, if the radical is involving in resonance which is weakest bond strength.

Bromination:

1-Methylcyclohexane is undergoes radical bromination which forms 1-bromo-1-methylcyclohexane therefore, bromination will occur where the tertiary radical is present. Because bromination will occur selectively in tertiary alkyl radical. (bromination reactions are more selective reaction)

Answer 12

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Answer 15

Ch. 12.2 - Prob. 1P Ch. 12.2 - Write the steps for formation of...Ch. 12.3 - Prob. 3P Ch. 12.4 - How many alkyl chlorides are obtained from...Ch. 12.4 - Prob. 6P Ch. 12.5 - Prob. 8P Ch. 12.5 - a. Would chlorination or bromination produce a...Ch. 12.5 - Show how the following compounds could be prepared...Ch. 12.6 - Prob. 12P Ch. 12.7 - Prob. 13P

Solution Summary: The author explains that the major product obtained on treating the compounds in problem 29 should be identified.

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