To identify:
The mRNA sequence and orientation from the given sequence in non- template strand.
Introduction:
The central dogma of biology is that the DNA codes for RNA which guides the synthesis of proteins. RNA is
Answer to Problem 30A
The mRNA sequence would be 5’AUG CCA GUC AUC 3’.
The amino acid sequence is methionine- proline- valine- isoleucine.
Explanation of Solution
Each DNA molecule consists of two strands. Both the strands have complementary base pairs. During transcription, the two strands of DNA unwind. One strand serves as a template to synthesize new mRNA molecule while the other strand that remains unused is called the non- template strand.
It is given that the sequence in non- template strand is as follows:
5’ATGCCAGTCATC 3’ The sequence in template strand would be complementary to the sequence in non- template strand. Its orientation will be from 3’ to 5’.
Hence, sequence in template strand would be 3’TACGGTCAGTAG 5’.
Through transcription, the DNA code is transferred to mRNA. The mRNA transcript is manufactured in a 5’ to 3’ direction adding each new
So the mRNA sequence would be 5’AUGCCAGUCAUC 3’.
The dictionary of genetic code helps in finding the amino acids coded by the codons in mRNA.
AUG codes for methionine
CCA codes for proline
GUC codes for valine
AUC codes for isoleucine
Hence, the amino acid sequence is methionine- proline- valine- isoleucine
Chapter 12 Solutions
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