Explanation The line through the point P ( a , b ) of slope m = s t for any s and t with t ≠ 0 will be parameterized by: x = a + t u , y = b + s u Given: Point P = ( 2 , 5 ) and line y = 4 x − 3 Formula Used: To find out the slope of the straight line is given by: y = m x + c , where m is the slope Perpendicular lines have slopes that are negative reciprocals that are − 1 m Calculation: First we have to find the slope of the line, so the slope of the line y = 4 x − 3 is m = 4 Now, the slope of a perpendicular line is − 1 4 Now, m = s t s = − 1

4th Edition

ISBN: 9781319323394

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 12, Problem 2CRE

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We need to determine parametric equations for the line through $P = (2, 5)$ perpendicular to the line $y = 4 x - 3$ .

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We need to determine parametric equations for the line through P = ( 2 , 5 ) perpendicular to the line y = 4 x − 3 .

Solution Summary: The author explains the parametric equations for the line through P = ( 2, 5 ) perpendicular to y = 4 x 3.

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We need to determine parametric equations for the line through $P = (2, 5)$ perpendicular to the line $y = 4 x - 3$ .

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Chapter 12 Solutions

We need to determine parametric equations for the line through P = ( 2 , 5 ) perpendicular to the line y = 4 x − 3 .

Solution Summary: The author explains the parametric equations for the line through P = ( 2, 5 ) perpendicular to y = 4 x 3.

Concept explainers

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We need to determine parametric equations for the line through P=(2,5) perpendicular to the line y=4x−3.

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Chapter 12 Solutions

We need to determine parametric equations for the line through $P = (2, 5)$ perpendicular to the line $y = 4 x - 3$ .