1 SEM ACC W/RAVEN CARDED
12th Edition
ISBN: 9781265486297
Author: Raven
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Textbook Question
Chapter 12, Problem 2A
If the two genes in the previous question showed complete linkage, what would you predict for an F2
a. 1 red tall:2 pink short:1 white short
b. 1 red tall:2 red short:1 white short
c. 1 pink tall:2 red tall:1 white short
d. 1 red tall:2 pink tall:1 white short
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Which of the following applies to the Hardy-Weinberg expression:p2 + 2pq + q2?a. Knowing either p2 or q2, you can calculate all the otherfrequencies.b. It applies to Mendelian traits that are controlled by one pairof alleles.c. 2pq = heterozygous individualsd. It can be used to determine the genotype and allelefrequencies of the previous and the next generations.e. All of these are correct.
If blonde hair color is a recessive trait and one parent is heterozygous for the trait and the other parent is heterozygous for the trait, what are the chances that their offspring will have blonde hair?A. 25% (one in four)B 50% (two in four)C. 75% (three in four)D. 100% (four in four)
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When a plant breeder crossed two red roses, 78% of the offspring had red flowers and 22% had white flowers. According to these results, the allele for red flowers is most likely:
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Chapter 12 Solutions
1 SEM ACC W/RAVEN CARDED
Ch. 12.1 - Prob. 1LOCh. 12.1 - Explain the advantages of Mendels experimental...Ch. 12.2 - Evaluate the outcome of a monohybrid cross.Ch. 12.2 - Explain Mendels Principle of Segregation.Ch. 12.2 - Compare the segregation of alleles with the...Ch. 12.3 - Evaluate the outcome of a dihybrid cross.Ch. 12.3 - Explain Mendels Principle of Independent...Ch. 12.3 - Compare the segregation of alleles for different...Ch. 12.4 - Prob. 1LOCh. 12.4 - Prob. 2LO
Ch. 12.5 - Interpret data from testcrosses to infer unknown...Ch. 12.6 - Describe how assumptions in Mendels model result...Ch. 12.6 - Prob. 2LOCh. 12.6 - Explain the genetic basis for observed alterations...Ch. 12 - Inquiry question What confounding problems could...Ch. 12 - Prob. 2IQCh. 12 - Prob. 1DACh. 12 - Prob. 2DACh. 12 - Prob. 3DACh. 12 - What property distinguished Mendels investigation...Ch. 12 - The F1 generation of the monohybrid cross purple...Ch. 12 - The F1 plants from the previous question are...Ch. 12 - In a cross of Aa Bb cc X Aa Bb Cc, what is the...Ch. 12 - An organisms __________ is/are determined by its...Ch. 12 - Phenotypes like height in humans, which show a...Ch. 12 - Japanese four oclocks that are red and tall are...Ch. 12 - If the two genes in the previous question showed...Ch. 12 - What is the probability of obtaining an individual...Ch. 12 - Prob. 4ACh. 12 - Prob. 5ACh. 12 - Mendels model assumes that each trait is...Ch. 12 - z1. Create a Punnett square for the following...Ch. 12 - Explain how the events of meiosis can explain both...Ch. 12 - Prob. 3SCh. 12 - In mammals, a variety of genes affect coat color....
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- Which type of breeding is depicted in the picture below? SEE PHOTO ATTACHED A. Crossbreeding B. Inbreeding C. Line breeding D. Backcrossarrow_forwardIn a certain species of plant loci A, B and C have an additive effect on the colour of the flower. Alleles A, B, and C are dominant and alleles a, b and c are recessive. Knowing that a plant with genotype AAbbCc has a pink flower, which genotype, among the ones listed below, will produce the same phenotype? a. AABBCc b. AaBbCc c. Aabbcc d. aabbccarrow_forwardOne breed of cattle can be red, white, or roan. A cross of two roans produces equal numbers of whiteand red and twice as much roan. If a farmer wanted to breed an all-roan herd, which of the followingpairs would give him the best result? Explain your choice.a. roan and roan b. roan and red c. red and whitearrow_forward
- A 1:2:1 genotype ratio underlies the 3:1 phenotype ratio in the F2. The purple allele is designated A while the white allele is designated a. What are the genotypes of the 1:2:1 ratio? a. Aa:aa:AA b. AA:aa:Aa c. aa:Aa:AA d. a:AA:Aa e. AA:Aa:aaarrow_forwardIn certain plants, the tall trait is dominant to the short trait. If a heterozygous plant is crossed with a homozygous short plant, what is the percentage that the offspring will be short? a. 100% b. 50% c. 25% d. 0%arrow_forwardIf several pea plants with the genotype TtYy are crossed with pea plants with the genotype TtYy, what is the probability of producing the genotype TTYY in offspring? A. 1/16 B. 1/2 C.1/4 D.1/8arrow_forward
- One breed of cattle can be red, white, or roan. A cross of two roans produces equal numbers of whiteand red and twice as much roan. If a farmer wanted to breed an all-roan herd, which of the followingpairs would give him the best result? Explain why. a. roan and roan b. roan and red c. red and whitearrow_forwardIf a true-breeding pea plant with yellow seeds is crossed with a true-breeding pea plant with green seeds, what is the probability that the F1 generation will have green seeds? A. 0% B. 25% C. 75% D. 100% The hereditary units that Mendel called \factors" are known today as A. genes B. traits C. chromosomes D. characteristics In snapdragons, a cross between a red-owering snapdragon and a white-owering snapdragon will produce snapdragons that have pink owers. This is an example of A. complete dominance B. incomplete dominance C. X-linked dominance D. codominance. Which is the genotype of an individual that could be used in a dihybrid cross? A. RRYY B. RRYy C. RrYY D. RrYy Which disorder is a dominant trait? A. hemophilia B. cystic brosis C. Tay-Sachs disease D. Huntington's disease Genetic continuity In a family with three children, what is the probability that the rst child is a boy, the second child is a girl, and the third child is a boy? A. 12:5% B. 25% C. 50% D. 75%arrow_forwardA true breeding plant that produces yellow seeds is crossed with a true breeding plant that produces green seeds. All of the seeds of the offspring are yellow. Why? A. All of the offspring are homozygous for the yellow allele B. The alleles are codominant C. The yellow allele is dominant to the green allele D. The yellow allele is recessive to the green allele E. Yellow is an easier color to producearrow_forward
- Possible options: A. 1/9 B. 1/3 C. 1/6 D. 8/9arrow_forwarda. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5 Gametes – D1D2D3d4d5 × d1d2d3D4D5 F1 generation – D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…arrow_forwardA plant that is homozygous for the recessive yellow pod color is crossed with a plant that is heterozygous. Which phenotype will appear MOST in the offspring? A. There will only be plants with green pods. B. There will be more plants with green pods. C. There will be more plants with yellow pods. D. Plants with yellow and green pods will appear in equal numbers.arrow_forward
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