Explanation Given info: The satellite is 3.58 × 10 7 m above the surface of earth. The universal gravitational constant is 6.67 × 10 − 11 N ⋅ m 2 / kg 2 , mass of the earth is 5.97 × 10 24 kg and the radius of earth is 6.37 × 10 6 m . The formula for gravitational force exerted on satellite is, F = G m M e r 2 (1) Here, F is the gravitational force of attraction m is mass of satellite M e is mass of earth r is the distance between center of the earth and satellite G is the universal gravitational constant The expression for the distance between the center of the earth and satellite is, r = r e + d Here, r e is the radius of the earth d is the distance of the satellite from surface of the earth Substitute 6.37 × 10 6 m for r e and 3.58 × 10 7 m for d in the above expression. r = 6.37 × 10 6 m + 3.58 × 10 7 m = 4

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Chapter 12, Problem 26PCE

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The orbital speed of satellite.

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Physics, Books a la Carte Plus Mastering Physics with Pearson eText -- Access Card Package (5th Edition)

Ch. 12.1 - Rank the four systems shown in Figure 12-6 in...Ch. 12.2 - Suppose the Sun suddenly collapsed to half its...Ch. 12.3 - Satellite A orbits the Earth at the radius r,...Ch. 12.4 - Prob. 4EYU Ch. 12.5 - Prob. 5EYU Ch. 12.6 - If the radius of the Moons orbit around the Earth...Ch. 12 - It is often said that astronauts in orbit...Ch. 12 - When a person passes you on the street, you do not...Ch. 12 - Imagine bringing the tips of your index fingers...Ch. 12 - Does the radius vector of Mars sweep out the same...

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The orbital speed of satellite.

Solution Summary: The author explains the orbital speed of the satellite, the universal gravitational constant, and the distance between the earth and satellite.

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