Concept explainers
(a)
To interpret: The result that would obtained when epinephrine is added to a homogenate of normal liver which increases the activity of glycogen phosphorylase.
Introduction:
Epinephrine is also termed as adrenalin and it is a hormone which is used for the treatment of disorders such as anaphylaxis as well as cardiac arrest. It is used in emergency conditions.
(a)
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Explanation of Solution
Explanation:
The substance X is cAMP (cyclic adenosine monophosphate) and epinephrine hormone helps in the stimulation of glycogen phosphorylase by the activation of enzyme called adenylyl cyclase. It is involved in the formation of cAMP which serves as second messenger. Adenylyl cyclase is a membrane bound protein located in the plasma membrane. Its stimulation results in the formation of cAMP. After its formation, it helps in the regulation of several cellular processes. At the time of centrifugation, the enzyme adenylyl cyclase sediments into particulate fractions.
(b)
To interpret: The results that would be obtained when Substance X was produced and particulate fraction from centrifugation in (a) was treated with epinephrine.
Introduction:
cAMP is derived as a derivative of Adenosine triphosphate which is used as intercellular signal transduction several organisms. It acts a second messenger. It is stimulated by cAMP.
(b)
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Explanation of Solution
Explanation:
Glycogen phosphorylase is a type of phosphorylase enzyme which is directly induced by cAMP. As cAMP binds with protein kinase A (PKA), it results in its activation. The activation of protein kinase A results in the stimulation of enzyme glycogen phosphorylase.
(c)
To interpret: The results that would be obtained when substance X was heat stabled and its capacity for activation of phosphorylase is not affected by heat treatment.
Introduction:
cAMP is derived as a derivative of Adenosine triphosphate which is used as intercellular signal transduction several organisms. Epinephrine is also called as adrenalin and it is a hormone.
(c)
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Explanation of Solution
Explanation:
The cAMP is a heat-stable molecule and it is prepared by the treatment of ATP with barium hydroxide. Adenylate cyclase enzyme is involved in the conversion of adenosine triphosphate into cAMP in the presence of barium hydroxide. It stimulates cAMP dependent protein kinase A (PKA).
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Chapter 12 Solutions
SAPLINGPLUS FOR PRINCIPLES OF BIOCHEMIS
- Problem 15 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 4 of 15 4G 54% Done On the following Lineweaver-Burk -1 plot, identify the by dragging the Km point to the appropriate value. 1/V 40 35- 30- 25 20 15 10- T Км -15 10 -5 0 5 ||| 10 15 №20 25 25 30 1/[S] Г powered by desmosarrow_forward1:30 5G 47% Problem 10 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a competitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' s mM¹ with 10 mg pe 20 V' 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
- Problem 14 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:36 CO Problem 9 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of the catalytic efficiency (specificity constant) given that the enzyme concentration in this experiment is 5.0 μ.Μ. 1 [S] ¨‚ μM-1 1 V sμM-1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| O Гarrow_forwardProblem 11 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a noncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
- Problem 13 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 8 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of kcat given that the enzyme concentration in this experiment is 5.0 μM. 1 [S] , мм -1 1 V₁ s μM 1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward1:33 5G. 46% Problem 12 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without an uncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
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