1 SEM CARDLESS ACC W/RAVEN TEXT
1 SEM CARDLESS ACC W/RAVEN TEXT
12th Edition
ISBN: 9781265321062
Author: Raven
Publisher: MCGRAW-HILL HIGHER EDUCATION
bartleby

Concept explainers

bartleby

Videos

Textbook Question
Book Icon
Chapter 12, Problem 1IQ

Inquiry question What confounding problems could have been seen if Mendel had chosen another plant with exposed male and female structures?

Expert Solution & Answer
Check Mark
Summary Introduction

To determine: The problems that Mendel could face if he had chosen another plant with exposed male and female structures.

Introduction: The gametes fuse to initiate the development of an offspring, and the process is termed as Fertilization. The process occurs if male and female gametes are produced via the same organism. Fertilization is also termed as generative Fertilization, insemination, pollination, fecundation, syngamy, and impregnation.

Explanation of Solution

The problems related to self-fertilization or cross-fertilization were found if the Mendel had chosen another plant with exposed male and female structures. Cross-fertilization is the process fusion of male and female gametes of the same species and different individuals. Mendel chose a pea plant flower, and petals enclose both the male anther and the female carpel, and this leads self-fertilization taking place till the flower is disturbed. Mendel gathered pollen from the anthers of a white flower, then stored pollen onto the stigma of a purple flower with anthers excluded. The cross-fertilization yields all hybrid seeds that give rise to purple flowers, and using pollen from a white flower to fertilize a purple flower provides the same result.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
DNK dagi nukleotidlar va undan sintezlangan oqsildagi peptid boglar farqi 901 taga teng bo'lib undagi A jami H boglardan 6,5 marta kam bo'lsa DNK dagi jami H bog‘lar sonini toping
One of the ways for a cell to generate ATP is through the oxidative phosphorylation. In oxidative phosphorylation 3 ATP are produced from every one NADH molecule. In respiration, every glucose molecule produces 10 NADH molecules. If a cell is growing on 5 glucose molecules, how much ATP can be produced using oxidative phosphorylation/aerobic respiration?
If a cell is growing on 5 glucose molecules, how much ATP can be produced using oxidative phosphorylation/aerobic respiration?

Chapter 12 Solutions

1 SEM CARDLESS ACC W/RAVEN TEXT

Knowledge Booster
Background pattern image
Biology
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Text book image
Biology 2e
Biology
ISBN:9781947172517
Author:Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher:OpenStax
Text book image
Biology (MindTap Course List)
Biology
ISBN:9781337392938
Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher:Cengage Learning
Text book image
Concepts of Biology
Biology
ISBN:9781938168116
Author:Samantha Fowler, Rebecca Roush, James Wise
Publisher:OpenStax College
Text book image
Biomedical Instrumentation Systems
Chemistry
ISBN:9781133478294
Author:Chatterjee
Publisher:Cengage
Text book image
Biology Today and Tomorrow without Physiology (Mi...
Biology
ISBN:9781305117396
Author:Cecie Starr, Christine Evers, Lisa Starr
Publisher:Cengage Learning
How to solve genetics probability problems; Author: Shomu's Biology;https://www.youtube.com/watch?v=R0yjfb1ooUs;License: Standard YouTube License, CC-BY
Beyond Mendelian Genetics: Complex Patterns of Inheritance; Author: Professor Dave Explains;https://www.youtube.com/watch?v=-EmvmBuK-B8;License: Standard YouTube License, CC-BY