Principles of Information Security (MindTap Course List)
6th Edition
ISBN: 9781337102063
Author: Michael E. Whitman, Herbert J. Mattord
Publisher: Cengage Learning
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Chapter 12, Problem 19RQ
Program Plan Intro
Vulnerability assessment:
Vulnerability assessment is a process to identify the document vulnerabilities in physical and logical way. This system can be technical and non-technical. This assessment used to following accomplishments they are:
- This assessment is used to define the vulnerabilities in system or other internal and public networks.
- Ensuring the proper management system for remediation of risk.
- Collect the report for vulnerability status.
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Students have asked these similar questions
1. Create a Book record that implements the Comparable interface, comparing the
Book objects by year
- title: String
>
- author: String
- year: int
Book
+ compareTo(other Book: Book): int
+ toString(): String
Submit your source code on Canvas (Copy
your code to text box or upload.java file)
>
Comparable
2. Create a main method in Book record.
1) In the main method, create an array of 2 objects of Book with your choice of
title, author, and year.
2) Sort the array by year
3) Print the object. Override the toString in Book to match the example output:
@Javadoc Declaration Console X Properties
Book [Java Application] /Users/kuan/.p2/pool/plugins/org.eclipse.justj.openjdk.hotspo
[Book: year=1901, Book: year=2010]
Q5-The efficiency of a 200 KVA, single phase transformer is 98% when operating at full load 0.8
lagging p.f. the iron losses in the transformer is 2000 watt. Calculate the i) Full load copper losses ii)
half load copper losses and efficiency at half load. Ans: 1265.306 watt, 97.186%
2. Consider the following pseudocode for partition:
function partition (A,L,R)
pivotkey = A [R]
t = L
for i
L to R-1 inclusive:
if A[i] A[i]
t = t + 1
end if
end for
A [t] A[R]
return t
end function
Suppose we call partition (A,0,5) on A=[10,1,9,2,8,5]. Show the state of the list at the
indicated instances.
Initial A
After i=0 ends
After 1 ends
After i 2 ends
After i = 3 ends
After i = 4 ends
After final swap
10 19 285
[12 pts]
Chapter 12 Solutions
Principles of Information Security (MindTap Course List)
Ch. 12 - Prob. 1RQCh. 12 - Prob. 2RQCh. 12 - Prob. 3RQCh. 12 - Prob. 4RQCh. 12 - Prob. 5RQCh. 12 - Prob. 6RQCh. 12 - Prob. 7RQCh. 12 - Prob. 8RQCh. 12 - Prob. 9RQCh. 12 - Prob. 10RQ
Ch. 12 - Prob. 11RQCh. 12 - Prob. 12RQCh. 12 - Prob. 13RQCh. 12 - Prob. 14RQCh. 12 - Prob. 15RQCh. 12 - Prob. 16RQCh. 12 - Prob. 17RQCh. 12 - Prob. 18RQCh. 12 - Prob. 19RQCh. 12 - Prob. 20RQCh. 12 - Prob. 1ECh. 12 - Prob. 2ECh. 12 - Prob. 3ECh. 12 - Prob. 5ECh. 12 - Prob. 1CEDQCh. 12 - Prob. 2CEDQCh. 12 - Prob. 1EDM
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