PEARSON ETEXT ENGINEERING MECH & STATS
15th Edition
ISBN: 9780137514724
Author: HIBBELER
Publisher: PEARSON
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At time t = 14 s, the velocity of a particle moving in the x-y plane is v = 0.06i + 2.45j m/s. By time t = 14.06 s, its velocity has become
-0.04i + 2.31j m/s. Determine the magnitude day of its average acceleration during this interval and the angle 8 made by the average
acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis.
Answers:
aav =
0=
i
i
m/s²
The x-coordinate of a particle in curvilinear motion is given by x = 2t² - 3t where
x is in meters and t is in seconds. Also, the particle has an acceleration in the y-direction
given by a, 8- sec. If the velocity of the particle in the y-direction is 3 m/sec when t=0,
calculate the magnitudes of the velocity v and acceleration a of the particle when t=2 sec.
and the angles these vectors make with the x-axis at the same instant.
At time t = 18 s, the velocity of a particle moving in the x-y plane is v = 0.05i + 2.35j m/s. By time t = 18.05 s, its velocity has become
-0.15i + 2.17j m/s. Determine the magnitude day of its average acceleration during this interval and the angle made by the average
acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis.
Answers:
dav =
e=
m/s²
O
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