Chapter 12, Problem 192P

A particle which moves with curvilinear motion has coordinates in millimeters which vary with the time t in seconds according to x = 1.8t² -2.1t and y = 4.1t² - t3/1.2. Determine the magnitudes of the velocity v and acceleration a and the angles which these vectors make with the x-axis when t = 3.2 s. Answers: When t = 3.2 s, V = a = i i mm/s, 0,= i mm/s², ex O 0

Collars A and B slide along the fixed right-angle rods and are connected by a cord of length L= 7.1 m. Determine the acceleration of collar B when y = 2.8 m if collar A is given a constant upward velocity vĄ = 2.42 m/s. The acceleration of B is positive if to the right, negative if to the left. A L Answer: ag = m/s?

The y-coordinate of a particle in curvilinear motion is given by y = 5.2t³ -2.6t, where y is in inches and t is in seconds. Also, the particle has an acceleration in the x-direction given by ax = 3.8t in./sec². If the velocity of the particle in the x-direction is 12.2 in./sec when't = 0, calculate the magnitudes of the velocity v and acceleration a of the particle when t = 3.8 sec. Construct v and a in your solution. Answers: When t = 3.8 sec, V = a= MI MI in./sec in./sec²

At time t = 14 s, the velocity of a particle moving in the x-y plane is v = 0.13i + 2.60j m/s. By time t =14.09 s, its velocity has become -0.06i + 2.50j m/s. Determine the magnitude aay of its average acceleration during this interval and the angle e made by the average acceleration with the positive x-axis. The angle e is measured counterclockwise from the positive x-axis. Answers: dav = i m/s2 e =

Your answer is partially correct. A particle which moves with curvilinear motion has coordinates in millimeters which vary with the time t in seconds according to x = 1.5t2 - 5.2t and y = 2.3t2 - t/5.8. Determine the magnitudes of the velocity v and acceleration a and the angles which these vectors make with the x-axis when t= 1.4 s. Answers: When t = 1.4 s, mm/s, O, = i V = 5.51757 46.4108 4.3512 mm/s?, e, a = 46.4108

A particle which moves with curvilinear motion has coordinates in millimeters which vary with the time t in seconds according to x = 5.9t2 - 6.3t and y = 5.4t2 - t3/ 6.5. Determine the magnitudes of the velocity v and acceleration a and the angles which these vectors make with the x-axis when t = 4.7 s.Answers: When t = 4.7 s,

At time t = 14 s, the velocity of a particle moving in the x-y plane is v = 0.06i + 2.45j m/s. By time t = 14.06 s, its velocity has become -0.04i + 2.31j m/s. Determine the magnitude day of its average acceleration during this interval and the angle 8 made by the average acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis. Answers: aav = 0= i i m/s²

At time t = 12 s, the velocity of a particle moving in the x-y plane is v=0.08i + 2.28j m/s. By time t = 12.12 s, its velocity has become -0.08i + 2.14j m/s. Determine the magnitude day of its average acceleration during this interval and the angle 0 made by the average acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis. Answers: dav 0= Mi i m/s² O

Collars A and B slide along the fixed right-angle rods and are connected by a cord of length L = 3.2 m. Determine the acceleration of collar B when y = 1.3 m if collar A is given a constant upward velocity vA = 2.93 m/s. The acceleration of B is positive if to the right, negative if to the left. Answer: ag = i m/s?