MECHANICS OF MATERIALS
11th Edition
ISBN: 9780137605521
Author: HIBBELER
Publisher: RENT PEARS
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Textbook Question
Chapter 1.2, Problem 16P
Determine the resultant internal loadings on the cross section at points D and E. Assume the reactions at the supports A and B are vertical.
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Determine the reactions at A for the cantilever beam subjected to the distributed and concentrated loads.
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3.7 m
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The free-body diagram of the body is shown. The distributed loading has been replaced with a single equivalent force R at a
distance d to the right of point A. Find the magnitude of the force R and the distance d.
R
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d
Answer:
R =
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d =
i
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The beam supports the distributed load shown. Determine theresultant loadings acting on the cross-section e-e at point D.Assume the reactions at the supports A and B are vertical.
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B
●
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Chapter 1 Solutions
MECHANICS OF MATERIALS
Ch. 1.2 - Determine the resultant internal normal force,...Ch. 1.2 - Determine the resultant internal normal force,...Ch. 1.2 - Determine the resultant internal normal force,...Ch. 1.2 - Determine the resultant internal normal force,...Ch. 1.2 - Determine the resultant internal normal force,...Ch. 1.2 - Determine the resultant internal normal force,...Ch. 1.2 - The shaft is supported by a smooth thrust bearing...Ch. 1.2 - Determine the resultant internal normal and shear...Ch. 1.2 - Determine the resultant internal torque acting on...Ch. 1.2 - Determine the resultant internal loadings in the...
Ch. 1.2 - The shaft is supported by a smooth thrust bearing...Ch. 1.2 - Determine the resultant internal loading on the...Ch. 1.2 - Determine the resultant internal loading on the...Ch. 1.2 - The 800-lb load is being hoisted at a constant...Ch. 1.2 - Determine resultant internal loadings acting on...Ch. 1.2 - Determine the resultant internal normal force...Ch. 1.2 - Determine the resultant internal loadings on the...Ch. 1.2 - Determine the resultant internal loadings on the...Ch. 1.2 - The blade of the hacksaw is subjected to a...Ch. 1.2 - The blade of the hacksaw is subjected to a...Ch. 1.2 - Determine the resultant internal loadings on the...Ch. 1.2 - Determine the resultant internal loadings on the...Ch. 1.2 - The sky hook is used to support the cable of a...Ch. 1.2 - Determine the resultant internal torque acting on...Ch. 1.2 - Determine the resultant internal loadings acting...Ch. 1.2 - Determine the resultant internal loadings on the...Ch. 1.2 - Determine the resultant internal loadings on the...Ch. 1.2 - The metal stud punch is subjected to a force of...Ch. 1.2 - The metal stud punch is subjected to a force of...Ch. 1.2 - Determine the resultant internal loadings acting...Ch. 1.2 - A force of 80 N is supported by the bracket....Ch. 1.2 - The curved rod has a radius r and is fixed to the...Ch. 1.2 - The pipe assembly is subjected to a force of 600 N...Ch. 1.2 - If the drill bit jams when the handle of the hand...Ch. 1.2 - The curved rod AD of radius r has a weight per...Ch. 1.2 - A differential element taken from a curved bar is...Ch. 1.5 - The uniform beam is supported by two rods AB and...Ch. 1.5 - Determine the average normal stress on the cross...Ch. 1.5 - Determine the average normal stress on the cross...Ch. 1.5 - If the 600-kN force acts through the centroid of...Ch. 1.5 - Determine the average normal stress at points A,...Ch. 1.5 - Determine the average normal stress in rod AB if...Ch. 1.5 - A 175-lb woman stands on a vinyl floor wearing...Ch. 1.5 - Determine the largest intensity w of the uniform...Ch. 1.5 - The specimen failed in a tension test at an angle...Ch. 1.5 - The built-up shaft consists of a pipe AB and solid...Ch. 1.5 - If the material fails when the average normal...Ch. 1.5 - If the block is subjected to a centrally applied...Ch. 1.5 - The plate has a width of 0.5 m. If the stress...Ch. 1.5 - The member is subjected to a tensile force of 200...Ch. 1.5 - The boom has a uniform weight of 600 lb and is...Ch. 1.5 - Determine the average normal stress in each of the...Ch. 1.5 - If the average normal stress in each of the...Ch. 1.5 - Determine the maximum average shear stress in pin...Ch. 1.5 - The 150-kg bucket is suspended from end E of the...Ch. 1.5 - The 150-kg bucket is suspended from end E of the...Ch. 1.5 - If the pedestal is subjected to a compressive...Ch. 1.5 - The beam is supported by two rods AB and CD that...Ch. 1.5 - The beam is supported by two rods AB and CD that...Ch. 1.5 - The beam is supported by a pin at B and a short...Ch. 1.5 - The railcar docklight is supported by the...Ch. 1.5 - The plastic block is subjected to an axial...Ch. 1.5 - During a tension test, the wooden specimen is...Ch. 1.5 - The bar has a cross-sectional area of 400(106) m2....Ch. 1.5 - The bar has a cross-sectional area of 400(106) m2....Ch. 1.5 - Prob. 54PCh. 1.5 - The 2-Mg concrete pipe has a center of mass at...Ch. 1.5 - The 2-Mg concrete pipe has a center of mass at...Ch. 1.5 - The pier is made of material having a specific...Ch. 1.5 - Prob. 58PCh. 1.5 - The uniform bar, having a cross-sectional area of...Ch. 1.5 - Prob. 60PCh. 1.5 - Prob. 61PCh. 1.5 - The triangular blocks are glued along each side of...Ch. 1.5 - The triangular blocks are glued along each side of...Ch. 1.5 - Prob. 64PCh. 1.5 - Determine the maximum magnitude P of the load the...Ch. 1.5 - Prob. 66PCh. 1.5 - Prob. 67PCh. 1.7 - Rods AC and BC are used to suspend the 200-kg...Ch. 1.7 - If it is subjected to double shear, determine the...Ch. 1.7 - Determine the maximum average shear stress...Ch. 1.7 - If each of the three nails has a diameter of 4 mm...Ch. 1.7 - The strut is glued to the horizontal member at...Ch. 1.7 - Determine the maximum average shear stress...Ch. 1.7 - If the eyebolt is made of a material having a...Ch. 1.7 - If the bar assembly is made of a material having a...Ch. 1.7 - Determine the maximum force P that can be applied...Ch. 1.7 - The pin is made of a material having a failure...Ch. 1.7 - If the bolt head and the supporting bracket are...Ch. 1.7 - Six nails are used to hold the hanger at A against...Ch. 1.7 - If A and B are both made of wood and are 38 in....Ch. 1.7 - Prob. 70PCh. 1.7 - The connection is made using a bolt and nut and...Ch. 1.7 - Determine the required cross-sectional area of...Ch. 1.7 - Prob. 73PCh. 1.7 - The spring mechanism is used as a shock absorber...Ch. 1.7 - Prob. 75PCh. 1.7 - The hangers support the joist in such a way that...Ch. 1.7 - Prob. 77PCh. 1.7 - Prob. 78PCh. 1.7 - The two aluminum rods AB and BC have diameters of...Ch. 1.7 - The cotter is used to hold the two rods together....Ch. 1.7 - Prob. 81PCh. 1.7 - The 60mm60mm oak post is supported on the pine...Ch. 1.7 - Prob. 83PCh. 1.7 - Prob. 84PCh. 1.7 - The assembly consists of three disks A, B, and C...Ch. 1.7 - Prob. 86PCh. 1.7 - Prob. 87PCh. 1.7 - Prob. 88PCh. 1.7 - Prob. 89PCh. 1.7 - Prob. 90PCh. 1.7 - Prob. 91PCh. 1.7 - Prob. 92PCh. 1.7 - Prob. 93PCh. 1.7 - The aluminum bracket A is used to support the...Ch. 1.7 - If the allowable tensile stress for the bar is...Ch. 1.7 - The bar is connected to the support using a pin...Ch. 1 - The beam AB is pin supported at A and supported by...Ch. 1 - The long bolt passes through the 30-mm-thick...Ch. 1 - Determine the required thickness of member BC to...Ch. 1 - The circular punch B exerts a force of 2 kN on the...Ch. 1 - Determine the average punching shear stress the...Ch. 1 - The 150 mm by 150 mm block of aluminum supports a...Ch. 1 - The yoke-and-rod connection is subjected to a...Ch. 1 - The cable has a specific weight (weight/volume)...
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- Determine the support reactions for the beam on the left if w=150N/m and L=4m Don’t skip steps, please show all work.arrow_forwardThe beam shown in the image is subject to distributed and point loadings. 1.2 m 0.6 m -2 kN/m 1.2 m 1.8 m 1 1.5 kN 30° 1.2 m 1. Draw a free body diagram of the beam. 2. Determine the reactions at the supports A and B. y T 1 Barrow_forwardProvide the correct exponents and distances to make the singularity function given valid for the beam shown. VI = 8 kN, V2 = 8 kN, V3 = 200 mm, and V4 = 1100 mm. Determine the reaction forces at the supports. A v3 V37 (m) o The singularity functions are q = R1(x)ª – v1( – P)ª – v2(x – Q)ª + R2(x – R)ª - 2 - V = R1 – v1(x – D)B – v2(x – E)B + R2(x – F)® (1) M = R1x – v1(x – G)° – v2(x – H)° + R2(x – (2) From the given singularity functions, the exponents are A = B = C= The distances are P= mm Q = mm R= mm D= mm E= mm F= mm G= mm H= mm mm Reactions force R = kN and reaction force R2 = kNarrow_forward
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- The opposite beam is loaded with two forces P=19.2 KN and distributed load w=24 KN/m as shown. The reaction at A is P P W D E A В 1.8 m '0.6 m'0.6 m'0.6 m'arrow_forwardDetermine the resultant internal moment in kip-ft acting on the cross-section through point C. Assume the reactions at the supports A and B are vertical. P=2.74 Answer is: 16.44 kip-ft SHOW SOLUTIONarrow_forward5. Determine the resultant internal loadings on the cross section through point D. Assume the reactions at the supports A and B are vertical. Answer: NC = 0, VC = 4.50 kip, MC=31.5 kip ft 6 kN 3 kN/m B |C D 1.5 m 1.5 m- 0.5 m 0.5 marrow_forward
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