
Concept explainers
Interpretation:
The products for the given reactions are to be predicted.
Concept introduction:
Grignard reagent reactions with carbonyl groups are treated as acid base reactions.
The reaction of Grignard reagents with carbonyl groups yields secondary and tertiary alcohols as their products. These reactions are a two-step reaction. In first step, nucleophilic addition of carbonyl group takes place because Grignard reagent being nucleophilic uses its lone pair of electrons to form a bond with a carbon atom. This results in the formation of an alkoxide ion which remains associated with
In the second step, addition of aqueous HX causes the protonation of the alkoxide ion which leads to the formation of the alcohol and

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Chapter 12 Solutions
ORGANIC CHEMISTRY-WILEYPLUS ACCESS PKG.
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- Use the reaction coordinate diagram to answer the below questions. Type your answers into the answer box for each question. (Watch your spelling) Energy A B C D Reaction coordinate E A) Is the reaction step going from D to F endothermic or exothermic? A F G B) Does point D represent a reactant, product, intermediate or transition state? A/ C) Which step (step 1 or step 2) is the rate determining step? Aarrow_forward1. Using radii from Resource section 1 (p.901) and Born-Lande equation, calculate the lattice energy for PbS, which crystallizes in the NaCl structure. Then, use the Born-Haber cycle to obtain the value of lattice energy for PbS. You will need the following data following data: AH Pb(g) = 196 kJ/mol; AHƒ PbS = −98 kJ/mol; electron affinities for S(g)→S¯(g) is -201 kJ/mol; S¯(g) (g) is 640kJ/mol. Ionization energies for Pb are listed in Resource section 2, p.903. Remember that enthalpies of formation are calculated beginning with the elements in their standard states (S8 for sulfur). The formation of S2, AHF: S2 (g) = 535 kJ/mol. Compare the two values, and explain the difference. (8 points)arrow_forwardIn the answer box, type the number of maximum stereoisomers possible for the following compound. A H H COH OH = H C Br H.C OH CHarrow_forward
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