11th Edition

ISBN: 9780132719865

Author: EWEN, Dale

Publisher: PEARSON

Concept explainers

The term fluid pressure is coined as, the measurement of the force per unit area of a given surface of a closed container. It is a branch of physics that helps to study the properties of fluid under various conditions of force.

Gauge Pressure

Pressure is the physical force acting per unit area on a body; the applied force is perpendicular to the surface of the object per unit area. The air around us at sea level exerts a pressure (atmospheric pressure) of about 14.7 psi but this doesn’t seem …

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Textbook Question

Chapter 12, Problem 13RQ

Give one example of the effect of surface tension that is not described in this book.

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Chapter 12, Problem 12RQ

Chapter 12, Problem 14RQ

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I need help with part B. I cant seem to get the correct answer. Please walk me through what youre doing to get to the answer and what that could be

Question 6: Chlorine is widely used to purify municipal water supplies and to treat swimming pool waters. Suppose that the volume of a particular sample of Cl₂ gas is 8.70 L at 895 torr and 24°C. (a) How many grams of Cl₂ are in the sample? ⚫ Atomic mass of CI = 35.453 g/mol • Molar mass of Cl₂ = 2 x 35.453 = 70.906 g/mol Solution: Use the Ideal Gas Law: Step 1: Convert Given Values • Pressure: P = 895 torr → atm PV= = nRT 1 P = 895 × = 1.1789 atm 760 • Temperature: Convert to Kelvin: T24273.15 = 297.15 K • Gas constant: R = 0.0821 L atm/mol. K Volume: V = 8.70 L Step 2: Solve for n . PV n = RT n = (1.1789)(8.70) (0.0821)(297.15) 10.25 n = = 0.420 mol 24.405 Step 3: Calculate Mass of Cl₂ Final Answer: 29.78 g of Cl₂. mass nx M mass= (0.420)(70.906) mass= 29.78 g

E1 R₁ w 0.50 20 Ω 12 R₁₂ ww ΒΩ R₂ 60 E3 C RA w 15 Ω E2 0.25 E4 0.75 Ω 0.5 Ω

Chapter 12 Solutions

Applied Physics

Ch. 12.2 - A packing crate 2.50m 0.80m 0.45m weighs 1.41 ...Ch. 12.2 - A packing crate 2.50 m 20.0 cm 30.0 cm has a...Ch. 12.2 - A spring is stretched 24.0 in. by a force of 54.0...Ch. 12.2 - A 17.0-N force stretches a wire 0.650 cm. (a) What...Ch. 12.2 - A force of 36.0 N stretches a spring 18.0 cm. Find...Ch. 12.2 - A force of 5.00 N is applied to a spring whose...Ch. 12.2 - Each vertical steel column of an office building...Ch. 12.2 - Each vertical steel column of an office building...Ch. 12.2 - If the compression of each steel column in Problem...Ch. 12.2 - A coiled spring is stretched 40.0 cm by a 5.00-N...

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