Quantitative Chemical Analysis
Quantitative Chemical Analysis
9th Edition
ISBN: 9781464135385
Author: Daniel C. Harris
Publisher: W. H. Freeman
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Chapter 12, Problem 12.AE
Interpretation Introduction

Interpretation:

The concentration of K+ ion in the original sample should be calculated.

Concept introduction:

Molarity:

Molarity is a term of concentration, the number of moles present in Liter of solution is given by molarity and it is given by solution is given the ratio between mole to liter,

Molarity =Number of moleVolume(Liter)

Expert Solution & Answer
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Answer to Problem 12.AE

The concentration of K+ ion in the original sample is 1.256(±0.003%)×10-13M

Explanation of Solution

To calculate the concentration of K+ ion in the original sample EDTA

Given,

Volume of sample solution is 250.0mL

Volume of Zn2+ solution is 28.73 (±0.03)mL

Concentration of Zn2+ is 0.0437 (±0.0001)mL

The reactions are,

K++(C6H5)4B-KB(C6H5)4(s)4HgY2-+(C6H5)4B-+4H2OH3BO3+4C6H5Hg++4HY3-+OH-

From the above equation, the one mole of K+ reacting in first reaction and 4 molecule of EDTA reaction in 2 reaction.

From reaction 2, mole of EDTA is equal to mole of Zn2+

Concentration of K+ =14(moleofZn2+)Volumeoforginalsample=14[28.73 (±0.03) mL][0.043 7 (±0.0001) M]250.0(±0.1)mL=[14±(0%)][28.73 (±0.03) mL][0.043 7 (±0.0001) M]250.0(±0.040%)mL=1256(±0.255%)×10-13M=1.256(±0.003%)×10-13M

The given values are plugged in above equation to give the concentration of K+ ion in the original sample.

The concentration of K+ ion in the original sample is 1.256(±0.003%)×10-13M

Conclusion

The concentration of K+ ion in the original sample was calculated.

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