Chapter 12, Problem 12.96SP

(a)

Interpretation Introduction

To determine:

To calculate the van’t Hoff factor of an aqueous solution

GIVEN:

T_Solvent= 0°C,
T_solution= -4.65 °C ,
K_f=-1.86 °C Kg/mol,
i= ?

EXPLAINATION:

  $\begin{array}{l}\Delta {\text{T}}_{\text{B}}={\text{T}}_{\text{solution}}-{\text{ T}}_{\text{solvent}}\\ \text{m}=\frac{moleofsolute}{massofsolvent(kg)}\\ \text{m}=\left(\text{9}.\text{12}/\text{36}.\text{5}\right)/\left(\text{19}0/\text{1}000\right)\\ =0.\text{249}/0.\text{19 }\\ =\text{ 1}.\text{31 Kg}/\text{mol}\\ Now,\\ {\text{ΔT}}_{\text{f}}{\text{=T}}_{\text{solution}}{\text{- T}}_{\text{solvent}}\text{=}\text{k}\text{× m }\\ \text{ 0-(-4}\text{.65)}\text{ = 1}\text{.86 ×i}\text{1}\text{.31}\\ \text{ m= 1}\text{.908mol/Kg}\end{array}$

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