General Chemistry
General Chemistry
4th Edition
ISBN: 9781891389603
Author: Donald A. McQuarrie, Peter A. Rock, Ethan B. Gallogly
Publisher: University Science Books
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 12, Problem 12.82P
Interpretation Introduction

Interpretation:

The mass of HC2H3O2 produced has to be calculated.

Concept Introduction:

The formula to evaluate moles from molarity is given as follows:

  n=MV

Here,

M denotes molarity.

n denotes number of moles.

V denotes volume.

Mass percent is calculated by the formula as follows:

  Mass percent=Mass of soluteTotal Mass (100 %)

Expert Solution & Answer
Check Mark

Answer to Problem 12.82P

The mass of HC2H3O2 produced is 2.7744 g.

Explanation of Solution

The conversion factor to convert liters to milliliters is as follows:

  1 L=1000 mL

Hence convert 55 mL to L as follows:

  Volume=(55 mL)(1 L1000 mL)=0.055 L

Similarly, convert 100 mL to L as follows:

  Volume=(100 mL)(1 L1000 mL)=0.1 L

The formula to evaluate moles from molarity is given as follows:

  n=MV        (1)

Substitute 0.560 mol/L for M and 0.055 L for V in equation (1) to calculate moles of Cr2O72.

  n=(0.560 mol/L)(0.055 L)=0.0308 mol

Substitute 0.963 mol/L for M and 0.1 L for V in equation (1) to calculate moles of CH3CH2OH.

  n=(0.963 mol/L)(0.1 L)=0.0963 mol

The balanced reaction is given as follows:

  [3CH3CH2OH(aq)+2Cr2O72(aq)+16H+(aq)][3HC2H3O2(aq)+4Cr2+(aq)+11H2O(l)]        (2)

According to the stoichiometry of equation (2), 3 mol HC2H3O2 is produced by 2 mol Cr2O72, thus moles of HC2H3O2 produced by 0.0963 mol is calculated as follows:

  Moles of HC2H3O2=(0.0308 mol Cr2O72)(3 mol HC2H3O22 mol Cr2O72)=0.0462 mol HC2H3O2

Similarly, moles of HC2H3O2 produced by 0.0963 mol CH3CH2OH  is calculated as follows:

  Moles of HC2H3O2=(0.0963 mol CH3CH2OH)(3 mol HC2H3O23 mol CH3CH2OH)=0.0963 mol HC2H3O2

Since Cr2O72 yields less moles of HC2H3O2, it acts as limiting reagent and thus moles of HC2H3O2 produced is 0.0462 mol .

The formula to convert mass in gram to moles is as follows:

  Mass=(Number of moles)(Molar mass)        (3)

Substitute 0.0462 mol for moles and 60.052 g/mol for molar mass of HC2H3O2 in equation (3).

  Mass=(0.0462 mol)(60.052 g/mol)=2.7744 g

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Predict the organic products that form in the reaction below: H. H+ + OH H+ Y Note: You may assume you have an excess of either reactant if the reaction requires more than one of those molecules to form the products. In the drawing area below, draw the skeletal ("line") structures of the missing organic products X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Explanation Check Click and drag to start drawing a structure. G X C © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Access +
111 Carbonyl Chem Choosing reagants for a Wittig reaction What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 1 2 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Explanation Check Click and drag to start drawing a structure. × ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Use
A student proposes the transformation below in one step of an organic synthesis. There may be one or more reactants missing from the left-hand side, but there are no products missing from the right-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from the arrow. • Is the student's transformation possible? If not, check the box under the drawing area. . If the student's transformation is possible, then complete the reaction by adding any missing reactants to the left-hand side, and adding required catalysts, inorganic reagents, or other important reaction conditions above and below the arrow. • You do not need to balance the reaction, but be sure every important organic reactant or product is shown. + T X O O лет-ле HO OH HO OH This transformation can't be done in one step.

Chapter 12 Solutions

General Chemistry

Ch. 12 - Prob. 12.11PCh. 12 - Prob. 12.12PCh. 12 - Prob. 12.13PCh. 12 - Prob. 12.14PCh. 12 - Prob. 12.15PCh. 12 - Prob. 12.16PCh. 12 - Prob. 12.17PCh. 12 - Prob. 12.18PCh. 12 - Prob. 12.19PCh. 12 - Prob. 12.20PCh. 12 - Prob. 12.21PCh. 12 - Prob. 12.22PCh. 12 - Prob. 12.23PCh. 12 - Prob. 12.24PCh. 12 - Prob. 12.25PCh. 12 - Prob. 12.26PCh. 12 - Prob. 12.27PCh. 12 - Prob. 12.28PCh. 12 - Prob. 12.29PCh. 12 - Prob. 12.30PCh. 12 - Prob. 12.31PCh. 12 - Prob. 12.32PCh. 12 - Prob. 12.35PCh. 12 - Prob. 12.36PCh. 12 - Prob. 12.37PCh. 12 - Prob. 12.38PCh. 12 - Prob. 12.39PCh. 12 - Prob. 12.40PCh. 12 - Prob. 12.41PCh. 12 - Prob. 12.42PCh. 12 - Prob. 12.43PCh. 12 - Prob. 12.44PCh. 12 - Prob. 12.45PCh. 12 - Prob. 12.46PCh. 12 - Prob. 12.47PCh. 12 - Prob. 12.48PCh. 12 - Prob. 12.49PCh. 12 - Prob. 12.50PCh. 12 - Prob. 12.51PCh. 12 - Prob. 12.52PCh. 12 - Prob. 12.53PCh. 12 - Prob. 12.54PCh. 12 - Prob. 12.55PCh. 12 - Prob. 12.56PCh. 12 - Prob. 12.58PCh. 12 - Prob. 12.59PCh. 12 - Prob. 12.60PCh. 12 - Prob. 12.61PCh. 12 - Prob. 12.62PCh. 12 - Prob. 12.63PCh. 12 - Prob. 12.64PCh. 12 - Prob. 12.65PCh. 12 - Prob. 12.66PCh. 12 - Prob. 12.67PCh. 12 - Prob. 12.68PCh. 12 - Prob. 12.69PCh. 12 - Prob. 12.70PCh. 12 - Prob. 12.71PCh. 12 - Prob. 12.72PCh. 12 - Prob. 12.73PCh. 12 - Prob. 12.74PCh. 12 - Prob. 12.75PCh. 12 - Prob. 12.76PCh. 12 - Prob. 12.77PCh. 12 - Prob. 12.78PCh. 12 - Prob. 12.79PCh. 12 - Prob. 12.80PCh. 12 - Prob. 12.81PCh. 12 - Prob. 12.82PCh. 12 - Prob. 12.83PCh. 12 - Prob. 12.84PCh. 12 - Prob. 12.85P
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Text book image
Chemistry
Chemistry
ISBN:9781259911156
Author:Raymond Chang Dr., Jason Overby Professor
Publisher:McGraw-Hill Education
Text book image
Principles of Instrumental Analysis
Chemistry
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Cengage Learning
Text book image
Organic Chemistry
Chemistry
ISBN:9780078021558
Author:Janice Gorzynski Smith Dr.
Publisher:McGraw-Hill Education
Text book image
Chemistry: Principles and Reactions
Chemistry
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:Cengage Learning
Text book image
Elementary Principles of Chemical Processes, Bind...
Chemistry
ISBN:9781118431221
Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:WILEY
Acid-Base Titration | Acids, Bases & Alkalis | Chemistry | FuseSchool; Author: FuseSchool - Global Education;https://www.youtube.com/watch?v=yFqx6_Y6c2M;License: Standard YouTube License, CC-BY