Compound X is 2-propanol. When compound X is heated with strond acid, it dehydrates to form compound Y ( C 3 H 6 ). When compound X is oxidised, the compound Z ( C 3 H 6 O ) is formed, which cannot be oxidised further. Draw the condensed structural formulas and give the IUPAC names for the compound X, Y and Z. Concept Introduction: Oxidation is defined as the gain of oxygen atom or the loss of hydrogen atom. There is an increase in the number of carbon-hydrogen bond when an alcohol undergoes oxidation. Oxidation of the primary alcohol yields aldehydes , which on oxidation yields carboxylic acids , whereas the oxidation of the secondary alcohols yields ketones . Tertiary alcohols do no undergo oxidation. IUPAC stands for “International Union of Pure and Applied Chemistry”. IUPAC is the standard for naming the organic compounds. The aldehydes are named by substituting the “e” of the corresponding alkane with “al”. The carbon atom closest to the functional group is given the numbering. Also, the aldehyde group is not given any number because the aldehyde group is present at the end of the chain. The ketones are named by substituting “e” of the corresponding alkane with “one”. The numbering is done from the end of compounds which is nearest to the carbonyl group.

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Chapter 12, Problem 12.66CQ

Challenge Questions"http://www.w3.org/1999/xhtml" xmlns:epub="http://www.idpf.org/2007/ops" xmlns:m="http://www.w3.org/1998/Math/MathML">

Interpretation Introduction

Interpretation: Compound X is 2-propanol. When compound X is heated with strond acid, it dehydrates to form compound Y ( $C 3 H 6$ ). When compound X is oxidised, the compound Z ( $C 3 H 6 O$ ) is formed, which cannot be oxidised further. Draw the condensed structural formulas and give the IUPAC names for the compound X, Y and Z.

Concept Introduction:

Oxidation is defined as the gain of oxygen atom or the loss of hydrogen atom. There is an increase in the number of carbon-hydrogen bond when an alcohol undergoes oxidation.

Oxidation of the primary alcohol yields aldehydes, which on oxidation yields carboxylic acids, whereas the oxidation of the secondary alcohols yields ketones. Tertiary alcohols do no undergo oxidation.

IUPAC stands for “International Union of Pure and Applied Chemistry”. IUPAC is the standard for naming the organic compounds.

The aldehydes are named by substituting the “e” of the corresponding alkane with “al”. The carbon atom closest to the functional group is given the numbering. Also, the aldehyde group is not given any number because the aldehyde group is present at the end of the chain.

The ketones are named by substituting “e” of the corresponding alkane with “one”. The numbering is done from the end of compounds which is nearest to the carbonyl group.

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Answer 2

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Chapter 12, Problem 12.66CQ

Challenge Questions"http://www.w3.org/1999/xhtml" xmlns:epub="http://www.idpf.org/2007/ops" xmlns:m="http://www.w3.org/1998/Math/MathML">

Interpretation Introduction

Interpretation: Compound X is 2-propanol. When compound X is heated with strond acid, it dehydrates to form compound Y ( $C 3 H 6$ ). When compound X is oxidised, the compound Z ( $C 3 H 6 O$ ) is formed, which cannot be oxidised further. Draw the condensed structural formulas and give the IUPAC names for the compound X, Y and Z.

Concept Introduction:

Oxidation is defined as the gain of oxygen atom or the loss of hydrogen atom. There is an increase in the number of carbon-hydrogen bond when an alcohol undergoes oxidation.

Oxidation of the primary alcohol yields aldehydes, which on oxidation yields carboxylic acids, whereas the oxidation of the secondary alcohols yields ketones. Tertiary alcohols do no undergo oxidation.

IUPAC stands for “International Union of Pure and Applied Chemistry”. IUPAC is the standard for naming the organic compounds.

The aldehydes are named by substituting the “e” of the corresponding alkane with “al”. The carbon atom closest to the functional group is given the numbering. Also, the aldehyde group is not given any number because the aldehyde group is present at the end of the chain.

The ketones are named by substituting “e” of the corresponding alkane with “one”. The numbering is done from the end of compounds which is nearest to the carbonyl group.

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Answer 3

Question

Chapter 12, Problem 12.66CQ

Challenge Questions"http://www.w3.org/1999/xhtml" xmlns:epub="http://www.idpf.org/2007/ops" xmlns:m="http://www.w3.org/1998/Math/MathML">

Interpretation Introduction

Interpretation: Compound X is 2-propanol. When compound X is heated with strond acid, it dehydrates to form compound Y ( $C 3 H 6$ ). When compound X is oxidised, the compound Z ( $C 3 H 6 O$ ) is formed, which cannot be oxidised further. Draw the condensed structural formulas and give the IUPAC names for the compound X, Y and Z.

Concept Introduction:

Oxidation is defined as the gain of oxygen atom or the loss of hydrogen atom. There is an increase in the number of carbon-hydrogen bond when an alcohol undergoes oxidation.

Oxidation of the primary alcohol yields aldehydes, which on oxidation yields carboxylic acids, whereas the oxidation of the secondary alcohols yields ketones. Tertiary alcohols do no undergo oxidation.

IUPAC stands for “International Union of Pure and Applied Chemistry”. IUPAC is the standard for naming the organic compounds.

The aldehydes are named by substituting the “e” of the corresponding alkane with “al”. The carbon atom closest to the functional group is given the numbering. Also, the aldehyde group is not given any number because the aldehyde group is present at the end of the chain.

The ketones are named by substituting “e” of the corresponding alkane with “one”. The numbering is done from the end of compounds which is nearest to the carbonyl group.

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Answer 4

Question

Chapter 12, Problem 12.66CQ

Challenge Questions"http://www.w3.org/1999/xhtml" xmlns:epub="http://www.idpf.org/2007/ops" xmlns:m="http://www.w3.org/1998/Math/MathML">

Interpretation Introduction

Interpretation: Compound X is 2-propanol. When compound X is heated with strond acid, it dehydrates to form compound Y ( $C 3 H 6$ ). When compound X is oxidised, the compound Z ( $C 3 H 6 O$ ) is formed, which cannot be oxidised further. Draw the condensed structural formulas and give the IUPAC names for the compound X, Y and Z.

Concept Introduction:

Oxidation is defined as the gain of oxygen atom or the loss of hydrogen atom. There is an increase in the number of carbon-hydrogen bond when an alcohol undergoes oxidation.

Oxidation of the primary alcohol yields aldehydes, which on oxidation yields carboxylic acids, whereas the oxidation of the secondary alcohols yields ketones. Tertiary alcohols do no undergo oxidation.

IUPAC stands for “International Union of Pure and Applied Chemistry”. IUPAC is the standard for naming the organic compounds.

The aldehydes are named by substituting the “e” of the corresponding alkane with “al”. The carbon atom closest to the functional group is given the numbering. Also, the aldehyde group is not given any number because the aldehyde group is present at the end of the chain.

The ketones are named by substituting “e” of the corresponding alkane with “one”. The numbering is done from the end of compounds which is nearest to the carbonyl group.

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Answer 5

Chapter 12, Problem 12.66CQ

Challenge Questions"http://www.w3.org/1999/xhtml" xmlns:epub="http://www.idpf.org/2007/ops" xmlns:m="http://www.w3.org/1998/Math/MathML">

Interpretation Introduction

Interpretation: Compound X is 2-propanol. When compound X is heated with strond acid, it dehydrates to form compound Y ( $C 3 H 6$ ). When compound X is oxidised, the compound Z ( $C 3 H 6 O$ ) is formed, which cannot be oxidised further. Draw the condensed structural formulas and give the IUPAC names for the compound X, Y and Z.

Concept Introduction:

Oxidation is defined as the gain of oxygen atom or the loss of hydrogen atom. There is an increase in the number of carbon-hydrogen bond when an alcohol undergoes oxidation.

Oxidation of the primary alcohol yields aldehydes, which on oxidation yields carboxylic acids, whereas the oxidation of the secondary alcohols yields ketones. Tertiary alcohols do no undergo oxidation.

IUPAC stands for “International Union of Pure and Applied Chemistry”. IUPAC is the standard for naming the organic compounds.

The aldehydes are named by substituting the “e” of the corresponding alkane with “al”. The carbon atom closest to the functional group is given the numbering. Also, the aldehyde group is not given any number because the aldehyde group is present at the end of the chain.

The ketones are named by substituting “e” of the corresponding alkane with “one”. The numbering is done from the end of compounds which is nearest to the carbonyl group.

Answer 6

Chapter 12, Problem 12.66CQ

Challenge Questions"http://www.w3.org/1999/xhtml" xmlns:epub="http://www.idpf.org/2007/ops" xmlns:m="http://www.w3.org/1998/Math/MathML">

Interpretation Introduction

Interpretation: Compound X is 2-propanol. When compound X is heated with strond acid, it dehydrates to form compound Y ( $C 3 H 6$ ). When compound X is oxidised, the compound Z ( $C 3 H 6 O$ ) is formed, which cannot be oxidised further. Draw the condensed structural formulas and give the IUPAC names for the compound X, Y and Z.

Concept Introduction:

Oxidation is defined as the gain of oxygen atom or the loss of hydrogen atom. There is an increase in the number of carbon-hydrogen bond when an alcohol undergoes oxidation.

Oxidation of the primary alcohol yields aldehydes, which on oxidation yields carboxylic acids, whereas the oxidation of the secondary alcohols yields ketones. Tertiary alcohols do no undergo oxidation.

IUPAC stands for “International Union of Pure and Applied Chemistry”. IUPAC is the standard for naming the organic compounds.

The aldehydes are named by substituting the “e” of the corresponding alkane with “al”. The carbon atom closest to the functional group is given the numbering. Also, the aldehyde group is not given any number because the aldehyde group is present at the end of the chain.

The ketones are named by substituting “e” of the corresponding alkane with “one”. The numbering is done from the end of compounds which is nearest to the carbonyl group.

Answer 7

Chapter 12, Problem 12.66CQ

Challenge Questions"http://www.w3.org/1999/xhtml" xmlns:epub="http://www.idpf.org/2007/ops" xmlns:m="http://www.w3.org/1998/Math/MathML">

Interpretation Introduction

Interpretation: Compound X is 2-propanol. When compound X is heated with strond acid, it dehydrates to form compound Y ( $C 3 H 6$ ). When compound X is oxidised, the compound Z ( $C 3 H 6 O$ ) is formed, which cannot be oxidised further. Draw the condensed structural formulas and give the IUPAC names for the compound X, Y and Z.

Concept Introduction:

Oxidation is defined as the gain of oxygen atom or the loss of hydrogen atom. There is an increase in the number of carbon-hydrogen bond when an alcohol undergoes oxidation.

Oxidation of the primary alcohol yields aldehydes, which on oxidation yields carboxylic acids, whereas the oxidation of the secondary alcohols yields ketones. Tertiary alcohols do no undergo oxidation.

IUPAC stands for “International Union of Pure and Applied Chemistry”. IUPAC is the standard for naming the organic compounds.

The aldehydes are named by substituting the “e” of the corresponding alkane with “al”. The carbon atom closest to the functional group is given the numbering. Also, the aldehyde group is not given any number because the aldehyde group is present at the end of the chain.

The ketones are named by substituting “e” of the corresponding alkane with “one”. The numbering is done from the end of compounds which is nearest to the carbonyl group.

Answer 8

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Answer 11

Ch. 12.1 - Give the IUPAC name for each of the following: a....Ch. 12.1 - Give the IUPAC name for each of the following: a....Ch. 12.1 - Prob. 12.3QAP Ch. 12.1 - Draw the condensed structural formula, or...Ch. 12.1 - Prob. 12.5QAP Ch. 12.1 - Prob. 12.6QAP Ch. 12.1 - Draw the condensed structural formula, or...Ch. 12.1 - Draw the condensed structural formula, or...Ch. 12.2 - Prob. 12.9QAP Ch. 12.2 - Prob. 12.10QAP

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Chapter 12 Solutions