(a)
Interpretation:
The temperature at which austenite first starts transform on cooling should be calculated.
Concept Introduction:
Austenite is defined as a gamma-phase iron, it is a metallic, non-magnetic iron allotrope or a solid solution of iron, containing an alloying element. Austenite which is known to exist above the eutectoid temperature of 1000K of plain carbon steel. Other alloys of the steel contain different eutectoid temperatures. Austenite can remain stable at room temperature only in the presence of austenite stability elements, e.g. Ni in adequate quantity.
(b)
Interpretation:
The primary micro-constituents and its forms needs to be explained.
Concept Introduction:
The microconstituent of iron carbide includes austenite (
(c)
Interpretation:
The amount and composition of each phase as 728
Concept Introduction:
The plain iron-carbon alloys contain the amount of steel between 0.002% and 2.14 % by weight. The values keep on varying depending upon alloying elements like manganese, chromium, tungsten, nickel. Therefore, steel is called as iron-carbon alloy which does not undergo any kind of eutectic reaction. Iron is also able to take two crystalline forms, body-centered cubic structure, and face-centered cubic structure, which depends upon the temperature.
(d)
Interpretation:
The amount and composition of phases at 726
Concept Introduction:
The plain iron-carbon alloys contain the amount of steel between 0.002% and 2.14 % by weight. The values keep on varying depending upon alloying elements like manganese, chromium, tungsten, nickel. Therefore, steel is called as iron-carbon alloy which does not undergo any kind of eutectic reaction. Iron is also able to take two crystalline forms, BCC structure, and FCC structure, which depends upon the temperature.
(e)
Interpretation:
The amount and composition of microconstituent at 726
Concept Introduction:
The plain iron-carbon alloys contain the amount of steel between 0.002% and 2.14 % by weight. The values keep on varying depending upon alloying elements like manganese, chromium, tungsten, nickel. Therefore, steel is called as iron-carbon alloy which does not undergo any kind of eutectic reaction. Iron is also able to take two crystalline forms, BCC structure, and FCC structure, which depends upon the temperature.
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Chapter 12 Solutions
Essentials Of Materials Science And Engineering, Si Edition
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- A particular battery charger produces a constant current of 2.4 amperes to charge a 3.7 volt Iphone battery. It can fully charge a dead battery to full charge in 6 hours. (a) How many electrons are in the charged battery? (b) What amount of energy in Joules does the battery provide if it deliveres 0.25 amperes of current to a phone for 4 hours.arrow_forward3 Answer: 002 PROBLEM 15.188 The rotor of an electric motor rotates at the constant rate @₁ = 1800 rpm. Determine the angular acceleration of the rotor as the motor is rotated about the y axis with a constant angular velocity 2 x of 6 rpm counterclockwise when viewed from the positive y axis. α = (118.4 rad/s²)iarrow_forward12 in.. 10 in. PROBLEM 15.187 At the instant considered the radar antenna shown rotates about the origin of coordinates with an angular velocity @ = ai + @j+wk Knowing that (VA) = 15 in./s, (VB), 9 in./s, and (VB), = 18 in./s, determine (a) the angular velocity of the antenna, (b) the velocity of point A. B 10 in. Answers: = (0.600 rad/s)i - (2.00 rad/s) j + (0.750 rad/s)k V₁ = (20.0 in./s)i + (15.00 in./s) j + (24.0 in./s)karrow_forward
- please see fig 2 to answerarrow_forwardSOLVE ON PAPER DO NOT USE CHATGPT OR AIarrow_forwardA particular battery charger produces a constant current of 2.4 amperes to charge a 3.7 volt Iphone battery. It can fully charge a dead battery to full charge in 6 hours. (a) What amp-hour charge is stored in the charged battery? (b) How many coulombs does the charge battery hold? (c) Can the fully charged battery continuously operate a phone that needs 0.25 amperes of current for a 24 hour period of time?arrow_forward
- Design 5th order LPF with gain = Yo cut of freq=10KHZarrow_forwardThe current coil of a wattmeter is connected in the red line of a three-phase system. The voltage circuit can be connected between the red line and either the yellow line or the blue line by means of a two-way switch. Assuming the load to be balanced, show with the aid of a phasor diagram that the sum of the wattmeter indications obtained with the voltage circuit connected to the yellow and the blue lines respectively gives the total active power.arrow_forwardA wattmeter has its current coil connected in the yellow line, and its voltage circuit is connected between the red and blue lines. The line voltage is 400 V and the balanced load takes a line current of 30 A at a power factor of 0.7 lagging. Draw circuit and phasor diagrams and derive an expression for the reading on the wattmeter in terms of the line voltage and current and of the phase difference between the phase voltage and current. Calculate the value of the wattmeter indication. ANS: . Line amperes × line volts × sin φ = 8750 vararrow_forward
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