Chapter 12, Problem 12.20P

Interpretation Introduction

(a)

Interpretation:

The peaks of $2\text{-chloropentane}$ at $m/z=71$ and $m/z=70$ are to be classified as an even-electron and an odd-electron peak.

Concept introduction:

In mass spectrometry, an electron is lost to form a molecular ion. Two types of fragmentation occur. A stable molecular ion decomposes slowly and a peak with large relative abundance is detected in the mass spectrometer. If the molecular ion is unstable, it decomposes into several ions.

Interpretation Introduction

(b)

Interpretation:

The stable neutral molecule which can be lost to give the odd-electron ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as $\left(\text{M}+1\right)$ peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.

Interpretation Introduction

(c)

Interpretation:

The mechanism for the origin of each fragment ion is to be stated.

Concept introduction:

Mass spectroscopy is used to calculate mass to charge ratio of ions. Isotopic peak is also known as $\left(\text{M}+1\right)$ peak because it shows one unit mass more than the mass of the molecular ion because the molecule consists of different isotopes of an element.