Campbell Biology in Focus; Modified Mastering Biology with Pearson eText -- ValuePack Access Card -- for Campbell Biology in Focus (2nd Edition)
2nd Edition
ISBN: 9780134433776
Author: Lisa A. Urry, Michael L. Cain, Steven A. Wasserman
Publisher: PEARSON
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Chapter 12, Problem 11TYU
FOCUS ON EVOLUTION
Crossing over is thought to be evolutionarily advantageous because it continually shuffles genetic alleles into novel combinations. Until recently, it was thought that Y-linked genes might degenerate because they lack homologous genes on the X chromosome with which to recombine. However, when the Y chromosome was sequenced, eight large regions were found to be internally homologous to each other, and quite a few of the 78 genes represent duplicates. Explain how this might be beneficial.
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Cat fur coat color genetics is interesting. Orange fur is dominant (''B'') to black fur (''b'') and piebald, which is white spotting, is dominant (''S'') to non-white-spotted (''s''). Both of those genes are located on the X chromosome. In addition, in cats, somatic cells exhibit X-inactivation randomly, which explains why there are tortoiseshell cats (when heterozygous, have orange and black spots) as well as calico cats (orange and black but also with white spots). An orange and white spotted male is mated with a tortoiseshell female.
State the genotype of the male and the female.
Cat fur coat color genetics is interesting. Orange fur is dominant (''B'') to black fur (''b'') and piebald, which is white spotting, is dominant (''S'') to non-white-spotted (''s''). Both of those genes are located on the X chromosome. In addition, in cats, somatic cells exhibit X-inactivation randomly, which explains why there are tortoiseshell cats (when heterozygous, have orange and black spots) as well as calico cats (orange and black but also with white spots). An orange and white spotted male is mated with a tortoiseshell female.
Draw a dihybrid Punnet square to show the possible offspring:
It is also note that Chimpanzee has a chromosomal complement of 2N = 48, whereas human has 2N = 46. Interestingly, chromosomal banding patterns have revealed that the chromosome 12 and 13 of chimp show homology with human chromosome 2 (see figure for the alignment of human and chimp banding patterns). This is a good example of chromosomal aberration in evolution.
What type of chromosomal rearrangement is likely explained the
evolution of human chromosome 2 from the two chromosomes
of chimpanzee?
A. Translocation
B. Duplication
C. Inversion
D. Deletion
Chapter 12 Solutions
Campbell Biology in Focus; Modified Mastering Biology with Pearson eText -- ValuePack Access Card -- for Campbell Biology in Focus (2nd Edition)
Ch. 12.1 - Which one of Mendels laws relates to the...Ch. 12.1 - MAKE CONNECTIONS Review the description of meiosis...Ch. 12.1 - WHAT IF? Propose a possible reason that the first...Ch. 12.2 - A white-eyed female Drosophila is mated with a...Ch. 12.2 - Neither Tim nor Rhoda has Duchenne muscular...Ch. 12.2 - MAKE CONNECTIONS Consider what you learned about...Ch. 12.3 - When two genes are located on the same chromosome,...Ch. 12.3 - For each type of offspring of the testcross in...Ch. 12.3 - WHAT IF? Genes A, B, and C are located on the same...Ch. 12.4 - About 5% of individuals with Down syndrome have a...
Ch. 12.4 - WHAT IF? The ABO blood type locus has been mapped...Ch. 12.4 - MAKE CONNECTIONS The gene that is activated on the...Ch. 12.4 - Women born with an extra X chromosome (XXX) are...Ch. 12 - A man with hemophilia (a recessive, sex-linked...Ch. 12 - Pseudohypertrophic muscular dystrophy is an...Ch. 12 - A space probe discovers a planet inhabited by...Ch. 12 - Using the information from problem 3, scientists...Ch. 12 - A man with red-green color blindness (a recessive,...Ch. 12 - You design Drosophila crosses to provide...Ch. 12 - A wild-type fruit fly (heterozygous for gray body...Ch. 12 - Assume that genes A and B are 50 map units apart...Ch. 12 - Prob. 9TYUCh. 12 - SCIENTIFIC INQUIRY DRAW IT Assume you are mapping...Ch. 12 - FOCUS ON EVOLUTION Crossing over is thought to be...Ch. 12 - FOCUS ON INFORMATION The continuity of life is...Ch. 12 - SYNTHESIZE YOUR KNOWLEDGE Butterflies have an X-Y...
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- 18 The genes dumpy(dp) and clot(cl) are linked on chromosome II of Drosophila. A heterozygous female was testcrossed with a male. The progeny were • 11% dumpy. • 996 clot, • 4196 wildtype. 3996 dumpy-clot. What was the genotype of the heterozygous female? a) O dp dp"/cl cl D)O dp'dp/cl" cl DO dp'dp cl"cl 0 dp cl/ dp cl* e) O dpt cl/dp cl Boş bırakarrow_forwardIn an in situ hybridization experiment, a certain clonebound to only the X chromosome in a boy with no diseasesymptoms. However, in a boy with Duchenne musculardystrophy (X-linked recessive disease), it bound to theX chromosome and to an autosome. Explain. Could thisclone be useful in isolating the gene for Duchenne muscular dystrophy?arrow_forwardHello, i understand the question, but i only need to know which option is right, no need for explanation. I mean jsut say which option, thanks in advance.arrow_forward
- Part A You start your experiments with the eyeless mutation on chromosome IV. You cross the reciprocal translocation strain to the eyeless pure line to generate F, flies that are both translocation heterozygotes and Ee heterozygotes. You decide to testcross F, males and females in two separate experiments to take advantage of the fact that crossing over does not occur in male Drosophila. F, males x pure eyeless females (Note: There is no crossing over F, females x pure eyeless males (Note: Crossing over in the F, males.) Cross may occur in the F, females.) 4 eyeless, fully fertile 4 wild-type, semi-sterile 4 eyeless, semi-sterile 4 wild-type, fully fertile 4 eyeless, fully fertile 4 wild-type, semi-sterile 4 eyeless, semi-sterile 4 wild-type, fully fertile F, Progeny What can you conclude from these results? Select the two correct statements. > View Available Hint(s) O The F2 progeny in both experiments contain recombinants. O The F2 progeny contain recombinants only when F, females…arrow_forwardIf you assume Figure 2-15 also applies to mice and youirradiate male sperm with X rays (known to inactivategenes), what phenotype would you look for in progeny inorder to find cases of individuals with an inactivated SRYgene?arrow_forwardHi! I would love to get some help on the box-and arrow model question! :) A male individual who is XYSRY has the following genotype for the AMH gene on chromosome 19: AMH1 AMH2. The AMH1 allele codes for a protein that is capable of binding to the receptor for AMH. The AMH2 allele codes for a protein that is unable to bind with the receptor for AMH. Based on your understanding of biology, what is the likely phenotype of this individual? Humans have 23 pairs of chromosomes of which 22 pairs are autosomal and the 23rd pair is sex-linked.In a human female, the sex chromosome pair is represented as XX, whereas, in a human male, it is represented as XY.AMH is an anti-Mullerin hormone produced by the Sertoli cells in males and helps in the development of the sex organs. Each pair of chromosomes has a pair of genes called alleles at the same loci representing a single character. Each gene of an allele represents the expression of the character.A gene can either show expression or…arrow_forward
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