Chapter 12, Problem 11PE

Interpretation Introduction

Interpretation:

The molality of given sodium sulfate in a solution is to be determined and its comparison with its molarity is to be explained.

Concept Introduction:

Molality can be defined as the number of moles of solute that are dissolved in one kilogram of the solvent.

$m=\frac{\text{mol of solute}\left(n\right)}{\text{kg of solvent}}$

Molarity is expressed as the number of moles of solute that are dissolved per liter of the solution.

$M\text{= }\frac{\text{moles of solute}}{\text{L of solution}}$

Moles of a substance can be calculated as:

$n\text{ =}\frac{m}{M}$

Here, $m$ is the mass of the substance, $n$ is the number of moles and $M$ is the molar mass of the solvent.