Chapter 12, Problem 11E

a.

Program Plan Intro

Given:

File size = 1024 bytes

Payload size = 128 bytes

Systems are running IPv4.

We know that:

Size of TCP header = 20 bytes

Size of IP header = 20 bytes

Total size = 40 bytes overhead per segment

The file size can be divided into 8 segments each segment contains 128 bytes. So $\text{(40 + 128) × 8 = 1344 bytes}$ .

So totally 1344 bytes will be sent by 8 segments.

b.

Program Plan Intro

Given:

File size = 1024 bytes

Payload size = 128 bytes

Systems are running IPv6.

We know that:

Size of TCP header = 20 bytes

Fixed length of IPv6 = 40 bytes

Total size = 60 bytes overhead per segment

The file size can be divided into 8 segments each segment contains 128 bytes. So $\text{(60 + 128) × 8 = 1504 bytes}$.

So totally 1504 bytes will be sent by 8 segments.