Chapter 12, Problem 10PE

Interpretation Introduction

Interpretation:

The amount of sodium bromide needed to form $\text{25 g}$ of $1\%$ NaBr solution in water and the amount of water needed, in grams and in milliliters, are to be determined if the density of water at room temperature is $0.998\text{}\text{g/mL}$.

Concept Introduction:

The term percentage by mass $\left(\%w/w\right)$ shows the weight of solute dissolved in $100\text{ g}$ of solution. The percentage can be calculated as follows:

$\%=\frac{\text{ mass of solute }}{\text{ mass of solution}}\times 100$

Density is determined as follows:

$d=\frac{m}{V}$

Here, $d$ is density, $m$ is mass, and $V$ is volume.