Introductory Chemistry (6th Edition)
6th Edition
ISBN: 9780134302386
Author: Nivaldo J. Tro
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 12, Problem 101E
Interpretation Introduction
Interpretation:
The trend of melting point for the given
Concept Introduction:
The magnitude of dispersion forces depends upon how easily electron in the atom or molecule polarized in response to a dipole. Due to a larger size of the electron cloud, greater dispersion force is observed as electron are less tightly held by the nucleus. If other factors is same dispersion forces increases with molar mass.
The polar molecule containing a hydrogen atom that is directly bonded to high electronegative atom fluorine, nitrogen or oxygen exhibit additional interaction called hydrogen bonding.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Compounds 1 and 2 have the same molecular weight. Identify and discuss all intermolecular forces for each molecule and clearly explain in terms of intermolecular forces why one of the compounds has a higher boiling point than the other. In your writing be sure to indicate which boiling point (3 °C and 25 °C) belongs to which compound. Please be sure to write in clear, well-written sentences that clearly illustrate your understanding and correctly uses appropriate terminology.
Q10
Consider the data in the table.
Compound Melting point (°C) AHfus (kJ/mol) Boiling point (°C)
AHvap (kJ/mol)
HF
-83.11
4.577
19.54
25.18
HC1
-114.3
1.991
-84.9
17.53
HBr
-86.96
2.406
-67.0
19.27
HI
-50.91
2.871
-35.38
21.16
Using the data in the table, calculate ASfus and ASvap for HF.
ASfus =
J/(K · mol)
ASvap
J/(K · mol)
Determine the entropy change when 7.60 mol HF(g) condenses at atmospheric pressure.
AS =
J/K
Chapter 12 Solutions
Introductory Chemistry (6th Edition)
Ch. 12 - The first diagram shown here represents liquid...Ch. 12 - Prob. 2SAQCh. 12 - Prob. 3SAQCh. 12 - How many 20.0-g ice cubes are required to absorb...Ch. 12 - Prob. 5SAQCh. 12 - Prob. 6SAQCh. 12 - Prob. 7SAQCh. 12 - Prob. 8SAQCh. 12 - Prob. 9SAQCh. 12 - Prob. 10SAQ
Ch. 12 - Prob. 1ECh. 12 - Prob. 2ECh. 12 - What determines whether a substance is a solid,...Ch. 12 - 4. What are the properties of liquids? Explain the...Ch. 12 - 5. What are the properties of solids? Explain the...Ch. 12 - Prob. 6ECh. 12 - Prob. 7ECh. 12 - Prob. 8ECh. 12 - Prob. 9ECh. 12 - Why does a glass of water evaporate more slowly in...Ch. 12 - Prob. 11ECh. 12 - Prob. 12ECh. 12 - 13. Acetone evaporates more quickly than water at...Ch. 12 - Prob. 14ECh. 12 - Prob. 15ECh. 12 - Prob. 16ECh. 12 - 17. Explain why a steam burn from gaseous water at...Ch. 12 - Prob. 18ECh. 12 - Prob. 19ECh. 12 - Prob. 20ECh. 12 - Is the melting of ice endothermic or exothermic?...Ch. 12 - 22. Is the boiling of water endothermic or...Ch. 12 - Prob. 23ECh. 12 - Prob. 24ECh. 12 - 25. What is hydrogen bonding? How can you tell...Ch. 12 - Prob. 26ECh. 12 - Prob. 27ECh. 12 - Prob. 28ECh. 12 - Prob. 29ECh. 12 - Prob. 30ECh. 12 - Prob. 31ECh. 12 - 32. What is an atomic solid? What are the...Ch. 12 - Prob. 33ECh. 12 - Prob. 34ECh. 12 - Prob. 35ECh. 12 - Two samples of pure water of equal volume are put...Ch. 12 - Prob. 37ECh. 12 - Spilling water over your skin on a hot day will...Ch. 12 - Prob. 39ECh. 12 - Water is put into a beaker and heated with a...Ch. 12 - 41. Which causes a more severe burn: spilling 0.50...Ch. 12 - 42. The nightly winter temperature drop in a...Ch. 12 - Prob. 43ECh. 12 - Prob. 44ECh. 12 - 45. An ice chest is filled with 3.5 kg of ice at...Ch. 12 - Why does 50 g of water initially at 0 C warm more...Ch. 12 - In Denver, Colorado, water boils at 95. C....Ch. 12 - Prob. 48ECh. 12 - 49. How much heat is required to vaporize 33.8 g...Ch. 12 - How much heat is required to vaporize 43.9 g of...Ch. 12 - How much heat does your body lose when 2.8 g of...Ch. 12 - How much heat does your body lose when 4.86 g of...Ch. 12 - How much heat is emitted when 4.25 g of water...Ch. 12 - Prob. 54ECh. 12 - 55. The human body obtains 835 kJ of energy from a...Ch. 12 - 56. The human body obtains 1078 kJ from a candy...Ch. 12 - How much heat is required to melt 37.4 g of ice at...Ch. 12 - 58. How much heat is required to melt 23.9 g of...Ch. 12 - How much energy is released when 34.2 g of water...Ch. 12 - How much energy is released when 2.55 kg of...Ch. 12 - 61. How much heat is required to convert 2.55 g of...Ch. 12 - 62. How much heat is required to convert 5.88 g of...Ch. 12 - Prob. 63ECh. 12 - Prob. 64ECh. 12 - 65. What kinds of intermolecular forces are...Ch. 12 - Prob. 66ECh. 12 - Prob. 67ECh. 12 - What kinds of intermolecular forces are present in...Ch. 12 - Which substance has the highest boiling point?...Ch. 12 - Prob. 70ECh. 12 - One of these two substances is a liquid at room...Ch. 12 - Prob. 72ECh. 12 - 73. A flask containing a mixture of and is...Ch. 12 - 74. Explain why is a liquid at room temperature...Ch. 12 - Are CH3CH2CH2CH2CH3 and H2O miscible?Ch. 12 - Prob. 76ECh. 12 - Prob. 77ECh. 12 - 78. Determine whether a homogeneous solution forms...Ch. 12 - 79. Identify each solid as molecular, ionic, or...Ch. 12 - Prob. 80ECh. 12 - Identify each solid as molecular, ionic, or...Ch. 12 - Identify each solid as molecular, ionic, or...Ch. 12 - 83. Which solid has the highest melting point?...Ch. 12 - 84. Which solid has the highest melting point?...Ch. 12 - 85. For each pair of solids, determine which solid...Ch. 12 - For each pair of solids, determine which solid has...Ch. 12 - 87. List these substances in order of increasing...Ch. 12 - 88. List these substances in order of decreasing...Ch. 12 - 89. Ice actually has negative caloric content. How...Ch. 12 - Prob. 90ECh. 12 - An 8.5-g ice cube is placed into 255 g of water....Ch. 12 - A 14.7-g ice cube is placed into 324 g of water....Ch. 12 - 93. How much ice in grams would have to melt to...Ch. 12 - Prob. 94ECh. 12 - Prob. 95ECh. 12 - Prob. 96ECh. 12 - Draw a Lewis structure for each molecule and...Ch. 12 - Draw a Lewis structure for each molecule and...Ch. 12 - 99. The melting point of ionic solids depends on...Ch. 12 - Draw ionic Lewis structures for KF and CaO. Use...Ch. 12 - Prob. 101ECh. 12 - Prob. 102ECh. 12 - An ice cube at 0.00 C with a mass of 23.5 g is...Ch. 12 - Prob. 104ECh. 12 - Prob. 105ECh. 12 - Prob. 106ECh. 12 - Prob. 107ECh. 12 - Prob. 108ECh. 12 - Prob. 109QGWCh. 12 - Prob. 110QGWCh. 12 - Prob. 111QGWCh. 12 - Prob. 112QGWCh. 12 - Prob. 113DIA
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Methane, CH4, reacts with chlorine, Cl2, to produce a series of chlorinated hydrocarbons: methyl chloride (CH3Cl), methylene chloride (CH2Cl3), chloroform (CHCl3), and carbon tetrachloride (CCl4). Which compound has the highest vapor pressure at room temperature? Explain.arrow_forwardA 0.439 mol sample of liquid propanol (60.09 g/mol) is heated from 25.6°C to 328.3PC. The boiling point of propanol is 206.6°C. The specific heat of liquid propanol is 2.40 J/g°C. The specific heat of propanol vapor is 1.42 J/g°C. The enthalpy of vaporization for propanol is 47.5 kJ/mol. What is the energy change of this process, in kJ?arrow_forwardConsider the data in the table. Compound Melting point (°C) AHfus (kJ/mol) Boiling point (°C) AHvap (kJ/mol) HF -83.11 4.577 19.54 25.18 HCI -114.3 1.991 -84.9 17.53 HBr -86.96 2.406 -67.0 19.27 HI -50.91 2.871 35.38 21.16 Using the data in the table, calculate ASfus and A.Svap for HBr. ASfus= 13 ASvap 93 Determine the entropy change when 6.90 mol HBr(1) freezes at atmospheric pressure. 355 AS= J/(K-mol) J/(K - mol) J/K Question Source: McQuarrie, Rock, And Gallogly 4e General Chemistry | Publisher Universitarrow_forward
- A 0.488 mol sample of liquid propanol (60.09 g/mol) is heated from 25.7°C to 329.2C. The boiling point of propanol is 206.6°C. The specific heat of liquid propanol is 2.40 J/g°C. The specific heat of propanol vapor is 1.42 J/g°C. The enthalpy of vaporization for propanol is 47.5 kJ/mol.What is the energy change of this process, in kJ?arrow_forwardArrange the following in order of decreasing boiling point. Т HIC I H-C-c нн H-C Н Н I-O-I -С H H C-C-NH₂ H H-C-c Н Н Н I-о Н HHF FIC Н HTC H с I C I- -С-Н Н 1 Ч H 15 C-H Н Н Н H H H N С Н D KBr Н Н I-I H Н Н CH3 LICI Н нннннн HTC -Т Н 7 -C от Н IOI CIH с-с-н Н Нarrow_forwardThe AHvap of a certain compound is 16.96 kJ mol-¹ and its ASvap is 89.63 J. mol K-¹ What is the boiling point of this compound? boiling point: °Carrow_forward
- Which one of the liquids would you expect to have the lowest vapor pressure at room temperature with given boiling point data. O methyl Acetate CH3COOCH3 57.2 °C 36.1 °C pentane C5H12 water, H2O 100°C methanol, CH3OH O ethylene glycol, HO–CH2-CH2-OH 64.96°C 198°C octane C8H18 125.6 °Carrow_forwardExplain the following observations by reference to the type of bonding present and/or the forces between organic molecules: The compounds ethanol (CH3CH2OH) and formic acid (HCOOH) have molecular masses of 46 gmol-1 but different boiling points: Compound Boiling point Ethanol 78.5 °C Formic acid 100.8 °Carrow_forwardThe following compounds are liquid at -10 °C: diethyl ether, methanol, and ethylene glycol. Arrange the three compounds in order of increasing vapor pressure at -10 °C. Choose between 1 - lowest vapor pressure, 2, or 3 - highest vapor pressure. Note: Reference the Phase change properties of pure substances table for additional information. Ethylene glycol (Choose one) Methanol (Choose one) Diethyl ether (Choose one) Garrow_forward
- 3. Pure benzophenone melts at 48.1°C. Your sample of benzophenone began to freeze at 47.0°C. When you repeated this measurement, the sample again began to freeze at 47.0°C. Give at least two reasonable explanations for this observation.arrow_forwardRelating vapor pressure to vaporisation.arrow_forwardWhich has the lowest normal boiling point? N2 NaCl Hgarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
Introductory Chemistry: An Active Learning Approa...ChemistryISBN:9781305079250Author:Mark S. Cracolice, Ed PetersPublisher:Cengage Learning
EBK A SMALL SCALE APPROACH TO ORGANIC LChemistryISBN:9781305446021Author:LampmanPublisher:CENGAGE LEARNING - CONSIGNMENT
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
General Chemistry - Standalone book (MindTap Cour...
Chemistry
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Cengage Learning
Introductory Chemistry: An Active Learning Approa...
Chemistry
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Cengage Learning
EBK A SMALL SCALE APPROACH TO ORGANIC L
Chemistry
ISBN:9781305446021
Author:Lampman
Publisher:CENGAGE LEARNING - CONSIGNMENT
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Viscosity, Cohesive and Adhesive Forces, Surface Tension, and Capillary Action; Author: Professor Dave Explains;https://www.youtube.com/watch?v=P_jQ1B9UwpU;License: Standard YouTube License, CC-BY