The reason has to be explained for the non-Zaitsev elimination product of 3-methylcyclohexene when trans-1-bromo-2-methylcyclohexane treats with base. Concept introduction: E 2 elimination: Alkyl halide forms an alkene from the abstraction of the proton from the β-carbon atom followed by elimination of the halogen in a single step. Saytzeff's Rule: It is elimination reaction in which the formation of olefin on most hindered or highly substituted position. Given information: The structure of the product is shown below,

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81. a. Propose a mechanism for the following reaction: OH CH2=CHCHC=N b. What is the product of the following reaction? HO H₂O N=CCH2CH2CH OH HO CH3CCH=CH2 H₂O C=N 82. Unlike a phosphonium ylide that reacts with an aldehyde or a ketone to form an alkene a sulfonium ulia

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Chapter 11.SE, Problem 66AP

Interpretation Introduction

Interpretation:

The reason has to be explained for the non-Zaitsev elimination product of 3-methylcyclohexene when trans-1-bromo-2-methylcyclohexane treats with base.

Concept introduction:

E₂ elimination:

Alkyl halide forms an alkene from the abstraction of the proton from the β-carbon atom followed by elimination of the halogen in a single step.

Saytzeff's Rule:
It is elimination reaction in which the formation of olefin on most hindered or highly substituted position.

Given information:

The structure of the product is shown below,

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81. a. Propose a mechanism for the following reaction: OH CH2=CHCHC=N b. What is the product of the following reaction? HO H₂O N=CCH2CH2CH OH HO CH3CCH=CH2 H₂O C=N 82. Unlike a phosphonium ylide that reacts with an aldehyde or a ketone to form an alkene a sulfonium ulia

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