Organic Chemistry As a Second Language: First Semester Topics
Organic Chemistry As a Second Language: First Semester Topics
4th Edition
ISBN: 9781119110668
Author: David R. Klein
Publisher: WILEY
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Chapter 11.8D, Problem 11.92P
Interpretation Introduction

Interpretation:

The reagent used to accomplish the given transformation has to be identified.

Concept Introduction:

Radical Bromination is a process in which the bromine atom is obtained as radical due to irradiation and this attack the carbon atom to form the brominated product.  The bromine atom gets substituted in the more substituted carbon atom.

Elimination reactions are the one in which the groups are lost and the saturated bonds are converted to unsaturated bonds.  Usually the substitution reaction compete with elimination reaction.

Organic Chemistry As a Second Language: First Semester Topics, Chapter 11.8D, Problem 11.92P , additional homework tip  1

In elimination reaction, the beta proton is removed together with the leaving group to form a double bond.

E2 reaction proceeds through a single step without any formation of intermediates.  The base abstracts a proton form the substrate and the loss of leaving group also happens resulting in the formation of double bond.  E2 stands for bimolecular elimination.

The proton can be abstracted by the base in two different ways leading to a regiochemical outcome.  In the given reaction below, two alkenes are formed as products due to regiochemistry.

Organic Chemistry As a Second Language: First Semester Topics, Chapter 11.8D, Problem 11.92P , additional homework tip  2

The two alkenes that are formed can be given different names.  If the alkene is more substituted means it is known as Zaitsev product, and if the alkene formed is less substituted means it is known as Hofmann product.  Generally more substituted product is the major product (Zaitsev product).

If the reaction is performed with a sterically hindered base, the major product will be less substituted alkene (Hofmann product).  The regiochemical outcome can be decided by choosing the base.  Some of the sterically hindered bases are,

Organic Chemistry As a Second Language: First Semester Topics, Chapter 11.8D, Problem 11.92P , additional homework tip  3

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Chapter 11 Solutions

Organic Chemistry As a Second Language: First Semester Topics

Ch. 11.2 - Prob. 11.14PCh. 11.2 - Prob. 11.15PCh. 11.2 - Prob. 11.17PCh. 11.2 - Prob. 11.18PCh. 11.2 - Prob. 11.19PCh. 11.2 - Prob. 11.20PCh. 11.2 - PROBLEMS For each of the following, predict the...Ch. 11.2 - Prob. 11.23PCh. 11.2 - PROBLEMS For each of the following, predict the...Ch. 11.2 - Prob. 11.25PCh. 11.3 - Prob. 11.27PCh. 11.3 - Prob. 11.28PCh. 11.3 - Prob. 11.29PCh. 11.3 - PROBLEMS Predict the products for each of the...Ch. 11.3 - Prob. 11.31PCh. 11.3 - Prob. 11.32PCh. 11.4 - Prob. 11.34PCh. 11.4 - Prob. 11.35PCh. 11.4 - Prob. 11.36PCh. 11.4 - Prob. 11.37PCh. 11.4 - Prob. 11.39PCh. 11.4 - Prob. 11.40PCh. 11.4 - Prob. 11.41PCh. 11.4 - Prob. 11.42PCh. 11.4 - Prob. 11.44PCh. 11.4 - Prob. 11.45PCh. 11.4 - Prob. 11.46PCh. 11.4 - Prob. 11.47PCh. 11.5 - Prob. 11.49PCh. 11.5 - Prob. 11.50PCh. 11.5 - Prob. 11.51PCh. 11.5 - Prob. 11.52PCh. 11.5 - Prob. 11.54PCh. 11.5 - Prob. 11.55PCh. 11.5 - Prob. 11.56PCh. 11.5 - Prob. 11.57PCh. 11.6 - Prob. 11.59PCh. 11.6 - Prob. 11.60PCh. 11.6 - Prob. 11.61PCh. 11.6 - Prob. 11.62PCh. 11.7 - Prob. 11.64PCh. 11.7 - Prob. 11.65PCh. 11.7 - Prob. 11.66PCh. 11.7 - Prob. 11.67PCh. 11.7 - Prob. 11.68PCh. 11.7 - Prob. 11.69PCh. 11.8A - Prob. 11.71PCh. 11.8A - Prob. 11.72PCh. 11.8A - Prob. 11.73PCh. 11.8A - Prob. 11.74PCh. 11.8A - Prob. 11.75PCh. 11.8A - Prob. 11.76PCh. 11.8A - Prob. 11.77PCh. 11.8A - Prob. 11.78PCh. 11.8B - Prob. 11.80PCh. 11.8B - Prob. 11.81PCh. 11.8B - Prob. 11.82PCh. 11.8B - Prob. 11.83PCh. 11.8B - Prob. 11.84PCh. 11.8B - Prob. 11.85PCh. 11.8C - Prob. 11.87PCh. 11.8C - Prob. 11.88PCh. 11.8C - Prob. 11.89PCh. 11.8C - Prob. 11.90PCh. 11.8D - Prob. 11.92PCh. 11.8D - Prob. 11.93PCh. 11.8D - Prob. 11.94PCh. 11.8D - Prob. 11.95PCh. 11.8D - Prob. 11.96PCh. 11.8D - Prob. 11.97PCh. 11.9 - Prob. 11.99PCh. 11.9 - Prob. 11.100PCh. 11.9 - Prob. 11.101PCh. 11.9 - Prob. 11.102PCh. 11.9 - Prob. 11.103PCh. 11.9 - Prob. 11.104PCh. 11.10 - Prob. 11.106PCh. 11.10 - Prob. 11.107PCh. 11.10 - Prob. 11.108PCh. 11.10 - Prob. 11.109PCh. 11.11 - Prob. 11.111PCh. 11.11 - Prob. 11.112PCh. 11.11 - Prob. 11.113PCh. 11.11 - Prob. 11.114PCh. 11.11 - Prob. 11.115PCh. 11.11 - Prob. 11.116PCh. 11.12 - Prob. 11.118PCh. 11.12 - Prob. 11.119PCh. 11.12 - Prob. 11.120PCh. 11.12 - Prob. 11.121PCh. 11.12 - Prob. 11.122PCh. 11.12 - PROBLEMS Predict the products for each of the...
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