The product that will be formed in the given reaction has to be predicted. Concept Introduction: Addition reactions are the one in which the groups are added to an unsaturated double bond. The double bond is destroyed because the groups are added across the double bond. If the considered alkene is a symmetrical one, then there is no difference in the product obtained but if the alkene is an unsymmetrical one, then regiochemistry decides the products that are obtained. When two similar groups are added across a double bond, regiochemistry is irrelevant but stereochemistry can be relevant. When adding two different groups across the double bond of an unsymmetrical alkene, the regiochemistry becomes relevant and stereochemistry also. In simple words, it can be said that, when two different groups are added across a double bond, then regiochemistry becomes relevant. Stereochemistry can also be determined for the product obtained by the way of addition of groups that adds across the double bond. If the two groups add in the same side of the plane means it is known as syn addition and if the two groups add in the opposite side of the plane means it is known as anti addition. This can be done by considering the given alkene in a planar form by using wedge and dash bonds. In case of addition reaction involving two hydroxyl groups, by the choice of reagent, the fashion in which the hydroxyl group gets added can be controlled. Either syn-addition or anti-addition can be accomplished. In order to add the two hydroxyl group in a syn fashion, osmium tetroxide with hydrogen peroxide or by using potassium permanganate, sodium hydroxide is employed. The complete reaction profile for the syn addition of two hydroxyl groups can be summarized as shown below,

Question

Want to see the full answer?

Answer 1

Question

Chapter 11.11, Problem 11.112P

Interpretation Introduction

Interpretation:

The product that will be formed in the given reaction has to be predicted.

Concept Introduction:

Addition reactions are the one in which the groups are added to an unsaturated double bond. The double bond is destroyed because the groups are added across the double bond. If the considered alkene is a symmetrical one, then there is no difference in the product obtained but if the alkene is an unsymmetrical one, then regiochemistry decides the products that are obtained.

When two similar groups are added across a double bond, regiochemistry is irrelevant but stereochemistry can be relevant. When adding two different groups across the double bond of an unsymmetrical alkene, the regiochemistry becomes relevant and stereochemistry also. In simple words, it can be said that, when two different groups are added across a double bond, then regiochemistry becomes relevant.

Stereochemistry can also be determined for the product obtained by the way of addition of groups that adds across the double bond. If the two groups add in the same side of the plane means it is known as syn addition and if the two groups add in the opposite side of the plane means it is known as anti addition. This can be done by considering the given alkene in a planar form by using wedge and dash bonds.

In case of addition reaction involving two hydroxyl groups, by the choice of reagent, the fashion in which the hydroxyl group gets added can be controlled. Either syn-addition or anti-addition can be accomplished. In order to add the two hydroxyl group in a syn fashion, osmium tetroxide with hydrogen peroxide or by using potassium permanganate, sodium hydroxide is employed. The complete reaction profile for the syn addition of two hydroxyl groups can be summarized as shown below,

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

CHEMICAL KINETICS. Indicate the approximation methods for solving the rate equation.

TRANSMITTANCE เบบ Please identify the one structure below that is consistent with the 'H NMR and IR spectra shown and draw its complete structure in the box below with the protons alphabetically labeled as shown in the NMR spectrum and label the IR bands, including sp³C-H and sp2C-H stretch, indicated by the arrows. D 4000 OH LOH H₂C CH3 OH H₂C OCH3 CH3 OH 3000 2000 1500 HAVENUMBERI-11 1000 LOCH3 Draw your structure below and label its equivalent protons according to the peak labeling that is used in the NMR spectrum in order to assign the peaks. Integrals indicate number of equivalent protons. Splitting patterns are: s=singlet, d=doublet, m-multiplet 8 3Hb s m 1Hd s 3Hf m 2Hcd 2Had 1He 鄙视 m 7 7 6 5 4 3 22 500 T 1 0

Relative Transmittance 0.995 0.99 0.985 0.98 Please draw the structure that is consistent with all the spectral data below in the box and alphabetically label the equivalent protons in the structure (Ha, Hb, Hc ....) in order to assign all the proton NMR peaks. Label the absorption bands in the IR spectrum indicated by the arrows. INFRARED SPECTRUM 1 0.975 3000 2000 Wavenumber (cm-1) 1000 Structure with assigned H peaks 1 3 180 160 140 120 100 f1 (ppm) 80 60 40 20 0 C-13 NMR note that there are 4 peaks between 120-140ppm Integral values equal the number of equivalent protons 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 0.0 fl (ppm)