Calculate volume of oxygen needed to react with 55.2 gram of butane at 0.850atm and 25°C Conceptual Introduction: Molar mass of substance are given in periodic table. Element molar mass is in gram/mole. We can determine chemical amount of known substance in moles by dividing the substance mass in grams by substance molar mass. The ideal gas law or general gas equation is an equation for ideal gas. Equation as follows- PV = nRT Where, P = pressure of gas V =volume of gas N= no. of moles of gas (amount of substance in gas) R = Universal gas constant The gas constant R has a value 8.314J/mole Kelvin Given: Mass of butane: 55.2 grams Pressure = 0.850 atm Temperature = 25°C

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Chapter 11.7, Problem 63PP

Interpretation Introduction

Interpretation: Calculate volume of oxygen needed to react with 55.2 gram of butane at 0.850atm and 25°C

Conceptual Introduction: Molar mass of substance are given in periodic table. Element molar mass is in gram/mole. We can determine chemical amount of known substance in moles by dividing the substance mass in grams by substance molar mass.

The ideal gas law or general gas equation is an equation for ideal gas.

Equation as follows-

PV = nRT

Where, P = pressure of gas

V =volume of gas

N= no. of moles of gas (amount of substance in gas)

R = Universal gas constant

The gas constant R has a value 8.314J/mole Kelvin

Given:

Mass of butane: 55.2 grams

Pressure = 0.850 atm

Temperature = 25°C

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