To determine To calculate: The derivative of the given function f ( p ) = ( 6 p − 7 ) ( 11 p − 1 ) ( 4 p + 3 ) . Explanation Given: Function as, f ( p ) = ( 6 p − 7 ) ( 11 p − 1 ) ( 4 p + 3 ) Formula used: Quotient ruleas: y ′ ( x ) = v ( x ) ⋅ u ′ ( x ) − u ( x ) ⋅ v ′ ( x ) [ v ( x ) ] 2 Calculation: Let u ( p ) = 6 p − 7 with u ′ ( p ) = 6 . v ( x ) = 11 p − 1 with v ′ ( p ) = 11 z ( p ) = 4 p + 3 with z ′ ( p ) = 4 Apply the quotient rule and the product rule together, f ′ ( p ) = z ( p ) [ v ( p ) ⋅ u ′ ( p ) + u ( p ) ⋅ v ′ ( p ) ] − [ u ( p ) ⋅ v ( p ) ] z ′ ( p ) [ z ( p ) ] 2 = ( 4 p + 3 ) [ ( 6 p − 7

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ISBN: 9780134776323

Author: MULLINS

Publisher: PEARSON CUSTOM PUB.(CONSIGNMENT)

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Chapter 11.6, Problem 25E

To determine

To calculate: The derivative of the given function f(p)=(6p−7)(11p−1)(4p+3).

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Chapter 11.6, Problem 24E

Chapter 11.6, Problem 26E

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