EBK BROCK BIOLOGY OF MICROORGANISMS
15th Edition
ISBN: 8220103633352
Author: Stahl
Publisher: PEARSON
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Chapter 11.5, Problem 2MQ
- Explain the fate of transferred chromosomal DNA if recombination does not occur in the recipient cell.
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Chapter 11 Solutions
EBK BROCK BIOLOGY OF MICROORGANISMS
Ch. 11.1 - Distinguish between a mutation and a mutant.Ch. 11.1 - Distinguish between screening and selection.Ch. 11.1 - Prob. 3MQCh. 11.1 - Write a one-sentence definition of the term...Ch. 11.2 - Do missense mutations occur in genes encoding...Ch. 11.2 - Why do frameshift mutations generally have more...Ch. 11.2 - Prob. 1CRCh. 11.3 - Why are suppressor tRNA mutations not lethal?Ch. 11.3 - Which class of mutation, missense or nonsense, is...Ch. 11.3 - What is the difference between same-site and...
Ch. 11.4 - Prob. 1MQCh. 11.4 - Prob. 2MQCh. 11.4 - Prob. 1CRCh. 11.5 - Which protein, found in virtually all cells,...Ch. 11.5 - Explain the fate of transferred chromosomal DNA if...Ch. 11.5 - Prob. 3MQCh. 11.5 - What are heteroduplex regions of DNA and what...Ch. 11.6 - During transformation a cell usually incorporates...Ch. 11.6 - In genetic transformation, what is meant by the...Ch. 11.6 - QExplain why recipient cells do not successfully...Ch. 11.7 - Prob. 1MQCh. 11.7 - What is the major difference between generalized...Ch. 11.7 - Why is phage conversion considered beneficial to...Ch. 11.7 - QExplain how a generalized transducing particle...Ch. 11.8 - In conjugation, how are donor and recipient cells...Ch. 11.8 - Explain how rolling circle DNA replication allows...Ch. 11.8 - QWhat is a sex pilus and which cell type, F or F+,...Ch. 11.9 - In conjugation involving the F plasmid of...Ch. 11.9 - Prob. 2MQCh. 11.9 - Prob. 3MQCh. 11.9 - QWhat is a merodiploid and how does an F plasmid...Ch. 11.10 - Why is it usually more difficult to select...Ch. 11.10 - Why do penicillins not kill species of Archaea?Ch. 11.10 - Explain one type of conjugation in Archaea and how...Ch. 11.11 - Prob. 1MQCh. 11.11 - What is the significance of the terminal inverted...Ch. 11.11 - How can transposons be used in bacterial genetics?Ch. 11.11 - Prob. 1CRCh. 11.12 - Why is the CRISPR system considered a prokaryotic...Ch. 11.12 - Prob. 2MQCh. 11.12 - QExplain why incoming DNA recognized by a short...Ch. 11 - A constitutive mutant is a strain that...Ch. 11 - Although a large number of mutagenic chemicals are...Ch. 11 - Why is it difficult in a single experiment to...Ch. 11 - Prob. 4AQ
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- Answer number seven do what it says.arrow_forwardWhich of the following is the process that is "capable of destroying all forms of microbial life"? Question 37 options: Surgical scrub Sterilization Chemical removal Mechanical removalarrow_forwardAfter you feel comfortable with your counting method and identifying cells in the various stages of mitosis, use the four images below of whitefish blastula to count the cells in each stage until you reach 100 total cells, recording your data below in Data Table 1. (You may not need to use all four images. Stop counting when you reach 100 total cells.) After totaling the cells in each stage, calculate the percent of cells in each stage. (Divide total of stage by overall total of 100 and then multiply by 100 to obtain percentage.) Data Table 1Stage Totals PercentInterphase Mitosis: Prophase Metaphase Anaphase Telophase Cytokinesis Totals 100 100% To find the length of time whitefish blastula cells spend in each stage, multiply the percent (recorded as a decimal, in other words take the percent number and divide by 100) by 24 hours. (Example: If percent is 20%, then Time in Hours = .2 * 24 = 4.8) Record your data in Data…arrow_forward
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genetic recombination strategies of bacteria CONJUGATION, TRANSDUCTION AND TRANSFORMATION; Author: Scientist Cindy;https://www.youtube.com/watch?v=_Va8FZJEl9A;License: Standard youtube license