Explanation Formula used: Let f ( x ) be an exponential probability density function for a continuous random variable X , then f ( x ) = { ( 1 λ ) e − x λ if x ≥ 0 0 otherwise Expected value or mean ( µ ): μ = λ Calculation: Let X be continuous random variable that is exponentially distributed with λ = 1 . Substitute the value of λ in the formula for the exponential density function. f ( x ) = ( 1 λ ) e − x λ = ( 1 1 ) e − x 1 = e − x Thus, the uniform density function is f ( x ) = { e − x if x ≥ 0 0 otherwise

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ISBN: 9781323520192

Author: Pearson

Publisher: PEARSON C

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Chapter 11.4, Problem 39E

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To find: The mean µ and then the probability P(X≤μ).

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Chapter 11.4, Problem 38E

Chapter 11.4, Problem 40E

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Chapter 11 Solutions

FIN 108 ISU LOOSE >IP<

Ch. 11.1 - Evaluate the following, if it converges: 3dx(x1)2.Ch. 11.1 - Prob. 2MP Ch. 11.1 - Prob. 3MP Ch. 11.1 - Prob. 4MP Ch. 11.1 - Prob. 5MP Ch. 11.1 - Prob. 6MP Ch. 11.1 - Prob. 1ED Ch. 11.1 - Prob. 2ED Ch. 11.1 - Prob. 1E Ch. 11.1 - Prob. 2E

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The mean µ and then the probability P ( X ≤ μ ) .

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To find: The mean µ and then the probability P(X≤μ).

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