ETEXT CAMPBELL BIOLOGY IN FOCUS INSTANT
3rd Edition
ISBN: 9780135964422
Author: Urry
Publisher: PEARSON
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Chapter 11.3, Problem 3CC
WHAT IF? A rooster with gray feathers and a hen of the same phenotype produce 15 gray, 6 black, and 8 white chicks. What is the simplest explanation for the inheritance of these colors in chickens? What
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For number 15-24. In man, assume that spotted skin (S) is dominant over non-spotted skin (s) and that
wooly hair (W) is dominant over non-wooly hair (w). Cross a heterozygous parent (SsWw) with a
heterozygous parent (Ssww) Give genotypic and phenotypic ratios of offspring.
15-18. What is the probability of producing spotted skin with non-wooly hair?
8/16
4/16
3/16
6/16
8/16
A.
B.
C.
D.
E.
19-21. What is the probability of producing non-spotted skin with non-wooly hair?
A
2/16
B.
4/16
C.
1/16
D.
6/16
22-24. What is the probability of producing non-spotted skin with wooly hair?
A 3/16
В. 4/16
с. 1/16
D. 9/16
E. 8/16
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Chapter 11 Solutions
ETEXT CAMPBELL BIOLOGY IN FOCUS INSTANT
Ch. 11.1 - DRAW IT Pea plants heterozygous for flower...Ch. 11.1 - List all gametes that could be made by a pea plant...Ch. 11.1 - Prob. 3CCCh. 11.2 - For any gene with a dominant allele A and...Ch. 11.2 - Two organisms, with genotypes BbDD and BBDd, are...Ch. 11.2 - Prob. 3CCCh. 11.3 - Incomplete dominance and epistasis are both terms...Ch. 11.3 - Prob. 2CCCh. 11.3 - WHAT IF? A rooster with gray feathers and a hen of...Ch. 11.4 - Lucia and Jared each have a sibling with cystic...
Ch. 11.4 - MAKE CONNECTIONS In Table 11.1, note the...Ch. 11 - DRAW IT Two pea plants heterozygous for the...Ch. 11 - A man with type A blood marries a woman with type...Ch. 11 - A man has six fingers on each hand and six toes on...Ch. 11 - Prob. 4TYUCh. 11 - Flower position, stem length, and seed shape are...Ch. 11 - Prob. 6TYUCh. 11 - Prob. 7TYUCh. 11 - Prob. 8TYUCh. 11 - Prob. 9TYUCh. 11 - Prob. 10TYUCh. 11 - In tigers, a recessive allele that is pleiotropic...Ch. 11 - Prob. 12TYUCh. 11 - Prob. 13TYUCh. 11 - Imagine that you are a genetic counselor, and a...Ch. 11 - Prob. 15TYUCh. 11 - Prob. 16TYUCh. 11 - Prob. 17TYUCh. 11 - Prob. 18TYU
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- Inheritance of a single gene: 7. A tortoiseshell cat mates with an orange cat: What is the probability of their kitten having all-orange fur? [Choose ] [Choose ] 0.25 What is the probability of their kitten having tortoiseshell coloration? 0.5 0.875 1.0 0.625 What is the probability of their kitten having all-black fur? 0.375 0.33 0.75 What is the probability that their black kitten will be male? [Choose ] What is the probability that their tortoiseshell kitten will be male? [Choose ]arrow_forwardCrossing Pea Plants: Mendels Study of Single Traits Stem length in pea plants is controlled by a single gene. Consider the cross of a true-breeding long-stemmed variety to a true-breeding short-stemmed variety in which long stems are completely dominant. a. If 120 F1 plants are examined, how many plants are expected to be long stemmed? Short stemmed? b. Assign genotypes to both P1 varieties and to all phenotypes listed in (a). c. A long-stemmed F1 plant is self-crossed. Of 300 F2 plants, how many should be long stemmed? Short stemmed? d. For the F2 plants mentioned in (c), what is the expected genotypic ratio?arrow_forwardEXAMPLE PROBLEM Two black female mice are crossed with a brown male. In several litters, female I produced 9 black offspring and 7 brown; female II produced 57 black offspring. What deductions can you make about the inheritance of black and brown coat color in mice? What are the genotypes of the parents? Dominance and recessive describe which of two possible phenotypes are exhibited when two different alleles occur in the same individual.arrow_forward
- Q5. When Mendel crossed a large number of tall pea plants with short pea plants, all F1 plants were tall. The F2 generation was created by self-pollinating the F1 plants. (a) Complete a genetic cross of F1 to show the genotypes and phenotypes of the parents and offspring. (b) Complete a genetic cross of F2 to show the genotypes and phenotypes of the offspring. (c) State the ratio of phenotypes expected in the F2 offspring. (d) Mendel's First Law of inheritance states that, “...the alleles of a given locus segregate into separate gametes." Explain how the genetic diagram above proves this law. (AC 2.1)arrow_forwardplz complete thisarrow_forward??arrow_forward
- 13arrow_forwardCan you help this work?arrow_forward. Consider the imaginary trait, bristles with split-ends, a trait hypothesized to be X-linked dominant. In a cross, the P1 virgin females were homozygous wild type while the males had bristles with split-ends. The F1 84 males were all wild type while the 90 females all had split-ends. In addition, the data for the F2 generation revealed 26 wild type males, 35 wild type females, 29 split-end males and 40 split-end females. Is this what is to be expected? Use chi-square to prove your position.arrow_forward
- 5arrow_forward???arrow_forwardA true-breeding rabbit with agouti (mottled, grayish brown) fur crossed with a true-breeding rabbit with chinchilla (silver) fur produces all agouti offspring. A true-breeding chinchilla rabbit crossed with a true-breeding Himalayan rabbit (white fur with pigmented nose, ears, tail, and legs) produces all chinchilla offspring. A true-breeding Himalayan rabbit crossed with a true-breeding albino rabbit produces all Himalayan offspring. Explain the inheritance of the fur colors.arrow_forward
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