Explanation Charles’s law states that the volume for a given number of moles of a gas is directly roportional to its absolute temperature (in kelvin) if the pressure is held constant V α T ( V is the volume and T is the temperature of the gas) V T = constant V 1 T 1 = V 2 T 2 V 1 and V 2 are the initial and final volume of the gas T 1 and T 2 are the initial and final temperatures of the gas in kelvin. Or at constant pressure and constant amount, the ratio of volume and temperature of gas is always constant Given: Initial volume of the gas is 2.50 L and the initial temperature is 15 ° C Pressure and number of moles are constant Formula used: V 1 T 1 = V 2 T 2 (1) For conversion of temperature in ° C to kelvin ( K ) , we use the formula: 0 ° C = 273.15 K K = ° C + 273.15 (2) 1 L = 1000 ml a. V 1 = 2.50 L V 2 = 5.00 L T 1 = 15 ° C T 2 = ? Convert ° C to kelvin ( K ) using formula ( 2 ) 15 ° C = ( 15 + 273.15 ) K Thus T 1 = 288.15 K Substitute the values of V 1 , V 2 and T 1 i n formula (1): 2.50 288.15 = 5 T 2 Cross multiplying T 2 = 5 × 288.15 2.50 T 2 = 576.3 K Convert temperature in kelvin to ° C using formula ( 2 ) T 2 = 576.3 − 273.15 = 303.15 ° C a. V 1 = 2.50 L V 2 = 1250 mL T 1 = 15 ° C T 2 = ? Convert ° C to kelvin ( K ) using formula ( 2 ) 15 ° C = ( 15 + 273.15 ) K = 288.15 K Thus T 1 = 288.15 K Convert volume from m L into L 1000mL=1L 1250 ml = 1250 1000 = 1.25 L = V 2 Substitute the values of V 1 , V 2 and T 1 i n f o r m u l a ( 1 ) : 2

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Chapter 11.3, Problem 27PP

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Temperature in degree Celsius

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Temperature in degree Celsius

Solution Summary: The author explains that the volume of a gas is directly proportional to its absolute temperature (in kelvin) if the pressure is constant.

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To determine: Temperature in degree Celsius

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Chapter 11 Solutions

To determine:

Temperature in degree Celsius