Explanation Given Information: The provided equation of the curve is, x 2 + 4 x + y 2 + 2 y − 4 = 0 and point is ( 1 , − 1 ) . Formula used: The slope of tangent to a curve y = f ( x ) at point ( x , y ) is given by the derivative of the curve at that point. Calculation: Consider the provided equation of curve, x 2 + 4 x + y 2 + 2 y − 4 = 0 Now, find the derivative d y d x from x 2 + 4 x + y 2 + 2 y − 4 = 0 by taking the derivative term by term on both sides of the equation as, d d x ( x 2 ) + d d x ( 4 x ) + d d x ( y 2 ) + d d x ( 2 y ) − d d x ( 4 ) =

Mathematical Applications for the Management, Life, and Social Sciences

11th Edition

ISBN: 9781305108042

Author: Ronald J. Harshbarger, James J. Reynolds

Publisher: Cengage Learning

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Chapter 11.3, Problem 23E

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To calculate: The slope of the tangent line to the curve x2+4x+y2+2y−4=0 at (1,−1).

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Chapter 11.3, Problem 22E

Chapter 11.3, Problem 24E

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Chapter 11 Solutions

Mathematical Applications for the Management, Life, and Social Sciences

Ch. 11.1 - 1. Ch. 11.1 - 2. If Ch. 11.1 - Prob. 3CP Ch. 11.1 - 4. Find . Ch. 11.1 - Prob. 1E Ch. 11.1 - Prob. 2E Ch. 11.1 - Prob. 3E Ch. 11.1 - Prob. 4E Ch. 11.1 - Prob. 5E Ch. 11.1 - Find the derivatives of the functions in Problems...

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The slope of the tangent line to the curve x 2 + 4 x + y 2 + 2 y − 4 = 0 at ( 1 , − 1 ) .

Solution Summary: The author calculates the slope of the tangent line to the curve at (1,-1).

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To calculate: The slope of the tangent line to the curve x2+4x+y2+2y−4=0 at (1,−1).

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Chapter 11 Solutions