Pearson eText for Starting out with Visual C# -- Instant Access (Pearson+)
5th Edition
ISBN: 9780137502783
Author: Tony Gaddis
Publisher: PEARSON+
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Expert Solution & Answer
Chapter 11.3, Problem 11.10CP
Explanation of Solution
Abstract class:
Abstract class is a class which acts as a base class for derived class that may contain one or more abstract methods and there is no need to instantiate, but it requires the derived class to provide implementations for abstract methods.
- The keyword “abstract” is used to create an abstract class.
- A class is declared as abstract when the methods inside the class are declared as abstract without implementation.
- An abstract class is a set of abstract members and non-abstract members.
- The purpose of abstract class is to provide the common features to its derived class and need not be instantiated. That is, programmer won’t be able to create an object for abstract class.
- It can only contain the declaration part in abstract class.
- So the abstract method must be overridden in derived class to implement the abstract methods.
- The programmer must implement abstract method in derived class using keyword “override”...
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Students have asked these similar questions
2. Signed Integers
Unsigned binary numbers work for natural numbers, but many calculations use negative
numbers as well. To deal with this, a number of different methods have been used to represent
signed numbers, but we will focus on two's complement, as it is the standard solution for
representing signed integers.
2.1 Two's complement
• Most significant bit has a negative value, all others are positive. So, the value of an n-digit
-2
two's complement number can be written as: Σ2 2¹ di 2n-1 dn
• Otherwise exactly the same as unsigned integers.
i=0
-
• A neat trick for flipping the sign of a two's complement number: flip all the bits (0 becomes 1,
or 1 becomes 0) and then add 1 to the least significant bit.
• Addition is exactly the same as with an unsigned number.
2.2 Exercises
For questions 1-3, answer each one for the case of a two's complement number and an
unsigned number, indicating if it cannot be answered with a specific representation.
1. (15 pts) What is the largest integer…
can u solve this question
1. Unsigned Integers
If we have an n-digit unsigned numeral dn-1d n-2...do in radix (or base) r, then the value of that
numeral is
n−1
r² di
Σi=0
which is basically saying that instead of a 10's or 100's place we have an r's or
r²'s place. For binary, decimal, and hex r equals 2, 10, and 16, respectively.
Just a reminder that in order to write down a large number, we typically use the IEC or SI
prefixing system:
IEC: Ki = 210, Mi = 220, Gi = 230, Ti = 240, Pi = 250, Ei = 260, Zi = 270, Yi = 280;
SI: K=103, M = 106, G = 109, T = 10¹², P = 1015, E = 10¹8, Z = 1021, Y = 1024.
1.1 Conversions
a. (15 pts) Write the following using IEC prefixes: 213, 223, 251, 272, 226, 244
21323 Ki8 Ki
223 23 Mi 8 Mi
b. (15 pts) Write the following using SI prefixes: 107, 10¹7, 10¹¹, 1022, 1026, 1015
107 10¹ M = 10 M
=
1017102 P = 100 P
c. (10 pts) Write the following with powers of 10: 7 K, 100 E, 21 G
7 K = 7*10³
Chapter 11 Solutions
Pearson eText for Starting out with Visual C# -- Instant Access (Pearson+)
Ch. 11.1 - Prob. 11.1CPCh. 11.1 - Prob. 11.2CPCh. 11.1 - Prob. 11.3CPCh. 11.1 - Prob. 11.4CPCh. 11.1 - Prob. 11.5CPCh. 11.2 - Prob. 11.6CPCh. 11.2 - Prob. 11.7CPCh. 11.3 - Prob. 11.8CPCh. 11.3 - Prob. 11.9CPCh. 11.3 - Prob. 11.10CP
Ch. 11.3 - Prob. 11.11CPCh. 11.3 - Prob. 11.12CPCh. 11.4 - Prob. 11.13CPCh. 11.4 - Prob. 11.14CPCh. 11.4 - Prob. 11.15CPCh. 11.4 - Prob. 11.16CPCh. 11.4 - Prob. 11.17CPCh. 11.5 - Prob. 11.18CPCh. 11.5 - Prob. 11.19CPCh. 11.5 - Prob. 11.20CPCh. 11.5 - Prob. 11.21CPCh. 11 - Prob. 1MCCh. 11 - Prob. 2MCCh. 11 - Prob. 3MCCh. 11 - Prob. 4MCCh. 11 - Prob. 5MCCh. 11 - Prob. 6MCCh. 11 - Prob. 7MCCh. 11 - Prob. 8MCCh. 11 - Prob. 9MCCh. 11 - Prob. 10MCCh. 11 - Prob. 11MCCh. 11 - Prob. 12MCCh. 11 - Prob. 13MCCh. 11 - Prob. 14MCCh. 11 - Prob. 15MCCh. 11 - Prob. 16MCCh. 11 - Prob. 17MCCh. 11 - Prob. 18MCCh. 11 - Prob. 19MCCh. 11 - Prob. 1TFCh. 11 - Prob. 2TFCh. 11 - Prob. 3TFCh. 11 - Prob. 4TFCh. 11 - Prob. 5TFCh. 11 - Prob. 6TFCh. 11 - Prob. 7TFCh. 11 - Prob. 8TFCh. 11 - Prob. 9TFCh. 11 - Prob. 10TFCh. 11 - Prob. 11TFCh. 11 - Prob. 12TFCh. 11 - Prob. 1SACh. 11 - Prob. 2SACh. 11 - Prob. 3SACh. 11 - Prob. 4SACh. 11 - Prob. 5SACh. 11 - Prob. 6SACh. 11 - Prob. 7SACh. 11 - Prob. 8SACh. 11 - Prob. 9SACh. 11 - Prob. 10SACh. 11 - Prob. 11SACh. 11 - Prob. 1AWCh. 11 - Prob. 2AWCh. 11 - Prob. 3AWCh. 11 - Prob. 4AWCh. 11 - Prob. 5AWCh. 11 - Prob. 6AWCh. 11 - Prob. 7AWCh. 11 - Prob. 8AWCh. 11 - Prob. 1PPCh. 11 - Prob. 2PPCh. 11 - Prob. 3PPCh. 11 - PERSON AND CUSTOMER Classes Design a class named...Ch. 11 - Prob. 5PPCh. 11 - Prob. 6PP
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