Explanation Definition used: “Standard q uadratic equation: “An equation in which the variable appears to the second power, but to no higher power, is called a quadratic equation . A standard quadratic equation can be expresses as, a x 2 ︸ + b x ︸ + c ︸ = 0 ↓ ↓ ↓ [ x 2 -term ] [ x -term ] [ Constant term ] That is every quadratic equation must have x 2 -term, but the x -term or constant tem may be missing.” Procedure used: 1. Identify the values of a , b and c by comparing the given equation with the standard quadratic equation a x 2 + b x + c = 0 . 2. Substitute the values of a , b and c into the quadratic equation formula x = − b ± b 2 − 4 a c 2 a . 3. Simplify the equation for x . 4. Check the solution by back substituting the values of x in the original equation. Calculation: The given quadratic equation is 6 x 2 − 13 x − 63 = 0 . Step 1: Identify the values of a , b and c by comparing the given equation with the standard quadratic equation a x 2 + b x + c = 0 . 6 x 2 ︸ + − 13 x ︸ + − 6 3 ︸ = 0 ↓ ↓ ↓ [ a = 6 ] [ b = − 13 ] [ c = − 63 ] Step 2: Substitute the values of a , b and c into the quadratic equation formula x = − b ± b 2 − 4 a c 2 a . x = − b ± b 2 − 4 a c 2 a = − ( − 13 ) ± ( − 13 ) 2 − 4 ( 6 ) ( − 63 ) 2 ( 6 ) Step 3: Simplify the equation for x

Mathematics for the Trades: A Guided Approach (11th Edition) (What's New in Trade Math)

11th Edition

ISBN: 9780134756967

Author: Hal Saunders, Robert Carman

Publisher: PEARSON

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Chapter 11.2, Problem 6BE

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To solve: The equation 6x2−13x−63=0.

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Chapter 11.2, Problem 5BE

Chapter 11.2, Problem 7BE

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Chapter 11 Solutions

Mathematics for the Trades: A Guided Approach (11th Edition) (What's New in Trade Math)

Ch. 11.1 - Simplify: 2(3 + 2y) 3y Ch. 11.1 - Prob. 2LC Ch. 11.1 - Solve each of the following systems of equations...Ch. 11.1 - Solve each of the following systems of equations...Ch. 11.1 - Solve each of the following systems of equations...Ch. 11.1 - Solve each of the following systems of equations...Ch. 11.1 - Prob. 5AE Ch. 11.1 - Solve each of the following systems of equations...Ch. 11.1 - Prob. 7AE Ch. 11.1 - Solve each of the following systems of equations...

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The equation 6 x 2 − 13 x − 63 = 0 .

Solution Summary: The author explains how to solve the equation 6x2-13x-63=0 by comparing the given equation with the standard quadratic equation.

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To solve: The equation 6x2−13x−63=0.

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Chapter 11 Solutions